how to download file from the server in c# .... below my code is

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here my code
is

and how to get column names insted of indexvalues

C#

public static void savefile_XML(string EmpId, string FirstName, string LastName, string MiddleName, string Gender, string DateOfBirth, string MobileNo, string EmailId, string Adress, string District, string State, string Country, string zip)
    {
        
        try
        {
           

                string[] arr1 = new string[] { EmpId, FirstName, LastName, MiddleName, Gender, DateOfBirth, MobileNo, EmailId, Adress, District, State, Country, zip };
                XmlDocument xmlDoc = new XmlDocument();
                XmlElement element = xmlDoc.CreateElement("data");

                for (int i = 0; i < arr1.Length; i++)
                {
                    XmlElement element1 = xmlDoc.CreateElement((i).ToString()); ;
                    element1.InnerText = arr1[i];
                    element.AppendChild(element1);
                    xmlDoc.AppendChild(element);



                }
               
                xmlDoc.Save(@" F:\srikanth\jqgrid\test.xml");
            
 }

        catch (Exception ex)
        {
            Elmah.ErrorLog.GetDefault(HttpContext.Current).Log(new Elmah.Error(ex, HttpContext.Current));
        }

here iam getting like this

XML

<0>2020</0>
  <1>narendra</1>
  <2>modi</2>
  <3>n</3>

iwant numbers insted of column names can u tell the code .....and how to save that file into our current project ...and how to download saved file ..plz help ...i dont no xml..iam new to the xml........

Posted 17-Jun-14 7:51am

srikanth492

Updated 19-Jun-14 0:20am

v3

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Comments

Kareem Abou Saad 18-Jun-14 4:44am

Probably because you are using xmlDoc.CreateElement((i).ToString()) ...

srikanth492 18-Jun-14 7:02am

thanks for replay..

srikanth492 18-Jun-14 4:51am

hi how to get column names insted of numbers can u tell me iam using xml and webmethod c#

srikanth492 18-Jun-14 6:41am

i save xml file into my project like this...Guid g;
g= Guid.NewGuid();
//g = GuidNewGuid();

var Mappingpath = HttpContext.Current.Server.MapPath(@".\");
xmlDoc.Save(Mappingpath +EmpId + g +".xml"); and how to download when click download button................

srikanth492 23-Jun-14 14:39pm

how to download when click the download button i can get entire row in pdf format downloaded in web browser i know code .see below
string filePath = ConfigurationManager.AppSettings["myFilePath"].ToString();
Guid g;
g = Guid.NewGuid();
string strFilename = EmpId + g + ".xml";
string Mappingpath = HttpContext.Current.Server.MapPath(filePath + strFilename);
xmlDoc.Save(Mappingpath);
return filePath + strFilename;
in this code one problem is there ...iam using static webpage when click the download it will just show values we only manuvally save(ctrl+s)....how can over come iam using jquery and json............this is my ajax code .....$.ajax({
type: "POST",
url: "EmployeeDetails.aspx/savefile_XML",
contentType: "application/json; charset=utf-8",
dataType: "json",
data: "{'getdata':" + JSON.stringify(getdata) + "}",
success: function (msg) {
window.open(msg.d, "Employyees");
var link = document.createElement("EmployeeDetails");
var fileName = data.substring(data.lastIndexOf('/') + 1);
link.download = fileName;
link.href = data;
link.click();
alert("downloaded");
},

srikanth492 23-Jun-14 14:41pm

window.open(msg.d, "Employyees"); it will works fine....
var link = document.createElement("EmployeeDetails");
var fileName = data.substring(data.lastIndexOf('/') + 1);
link.download = fileName; these line are not working

2 solutions

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Kareem Abou Saad · Accepted Answer · 2014-06-18T00:41:00

Solution 1

Instead of using

CSS

CreateElement((i).ToString());

Use

CreateElement((tagName));

Where tagName could be for example FirstName or LastName, so it ends up in the XML tag as

XML

<firstname></firstname>

To do this in the simplest way, create an array of fields holding literal strings like this:

C#

string[] fields = {"FirstName", "LastName", "Id"}; //etc..

Replace the

C#

(i).ToString()

with

C#

fields[i]

This should solve your problem.

Posted 18-Jun-14 0:41am

Kareem Abou Saad

Comments

srikanth492 18-Jun-14 6:59am

i got like this <tagname>2017

srikanth492 18-Jun-14 7:10am

<tagname>Male

srikanth492 18-Jun-14 7:00am

i write code like this ..XmlElement element1 = xmlDoc.CreateElement(("tagName"));
element1.InnerText = fields[i];

srikanth492 · Accepted Answer · 2014-06-23T08:33:00

solved my self using this code ....iam geting column name with help of this code.....

string EmpId = string.Empty;
var objects = JArray.Parse(getdata);
XmlDocument xmlDoc = new XmlDocument();
XmlElement element = xmlDoc.CreateElement("details");

foreach (JObject root in objects)
{
foreach (KeyValuePair<string,> app in root)
{
var appName = app.Key;//in this app.key getting column name
EmpId = (String)app.Value;// we can get empid
XmlElement element1 = xmlDoc.CreateElement(appName);
element1.InnerText = (String)app.Value;
element.AppendChild(element1);
xmlDoc.AppendChild(element);
}
}