Date Diff output in problem

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SQL-server-2000

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Hii ,

i want output like : 15:35 (HH:MI) OR 00:25 (HH:MI)

In date diff how i get this output in between two dates?

i have two dates :
2014-01-07 08:41:00.000
2014-01-07 17:29:00.000

Thank you ,

Posted 8-Jan-14 2:41am

RKparmar

Updated 8-Jan-14 2:43am

v2

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3 solutions

Solution 1

Try http://www.reflectionit.nl/Blog/2004/datediff-function-in-c[^].

Posted 8-Jan-14 2:43am

Abhinav S

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riteshsingh_jsr · Accepted Answer · 2014-01-08T02:51:00

Solution 2

Try this:

SELECT DATEDIFF(hour,'2014-01-01 03:24:16','2014-01-2 04:24:16')

exact which u want:-

DECLARE @INT INT
SET @INT = DATEDIFF(SECOND,GETDATE(),GETDATE()+1)
select
convert(varchar(10), (@INT/86400)) + ':' +
convert(varchar(10), ((@INT%86400)/3600))

Posted 8-Jan-14 2:51am

riteshsingh_jsr

Maciej Los · Accepted Answer · 2014-01-08T02:58:00

Solution 3

Have a look here:
Get time difference in the format "HH:MM:SS" for two different DateTime values in SQL Server[^]
how to display hh:mm format using DateDiff() function[^]

Posted 8-Jan-14 2:58am

Maciej Los

Comments

RKparmar 9-Jan-14 2:28am

HI ,

I use this but in this i m not calculate sum of time

select right('0' + cast(datediff(hh, '2014-01-02 08:30:00.000','2014-01-04 18:20:00.000') as varchar),2) +':' + right('0' + cast(datediff(mi, '2014-01-02 08:30:00.000','2014-01-04 18:20:00.000') % 60 as varchar),2) as HoursMin

i got more then one record from database . how to sum this all HoursMin column sum ?

Maciej Los 9-Jan-14 2:49am

Replace dates with column names ;)