Using CUB library for radix sort

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C++

CUDA

Can anyone please help me with how to use CUB library. I found out that it has a function that help me to radix sort on the basis of key value pair. But i am unable to use it even for a sample demo. so that later i can use it in my real project.

my requiremement for demo is:

       unsigned int *h_keys = (unsigned int*)malloc(numElements*sizeof(unsigned int));
       unsigned int *h_keysSorted = (unsigned int*)malloc(numElements*sizeof(unsigned int));
       unsigned int *h_values     = 0;
        h_values = (unsigned int *)malloc(numElements*sizeof(unsigned int));
	unsigned int *d_keys;
        unsigned int *d_values;
	cudaMalloc((void **)&d_keys, numElements*sizeof(unsigned int));
	cudaMalloc((void **)&d_values, numElements*sizeof(unsigned int));
	cudaMemset(d_keys,10, numElements*sizeof(unsigned int));
	cudaMemset(d_values,2, numElements*sizeof(unsigned int));
	for(int i=0; i < loopSize; ++i)   
	{ 
	    h_keys[i] = rand()%100;
	    h_values[i] = i; 
	}
	/**************************

          using cub library here and pass h_keys and h_values to its radix sort function 
and finally recive the sorted h_key value and in accordance of it the change in h_value.

        *************************/
		cudaMemcpy(d_keys, h_keys, loopSize * sizeof(unsigned int), cudaMemcpyHostToDevice);
		cudaMemcpy(d_values, h_values, loopSize * sizeof(unsigned int), cudaMemcpyHostToDevice);
		radixsort.sort(d_keys, d_values, loopSize, keybits);
	
		// Get results back to host for correctness checking
		cudaMemcpy(h_keysSorted, d_keys, loopSize * sizeof(unsigned int), cudaMemcpyDeviceToHost);
		cudaMemcpy(h_values, d_values, loopSize * sizeof(unsigned int), cudaMemcpyDeviceToHost);
		std::cout<<std::endl<<"After Sorting.............."<<std::endl;
	    for(int i =0; i<50 ;i++)
		{
			std::cout<<"h_values["<<i<<"]="<<h_values[i]<<"  "<<"h_keysSorted["<<i<<"]="<<h_keysSorted[i]<<std::endl;
		}

Thank in advance. please help it anyone has used cub libaray before...
http://nvlabs.github.io/cub/[^]