Python, range of 6, 3 positive numbers and 3 squared value.

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I would like to know the code of Performing the computation of rotating the list of elements if i type List1[4,5,6,16,25,36] it should give the output as [6,16,25,36,4,5]

Kindly give me an explaination of how it works

Thank you.

What I have tried:

#using the list function
list1 = []


#get user input
for i in range(6):
    num = int(input("Enter number: "))
    list1.append(num)


# Rotate the list to the left twice using the slicing rotation by 1

list1 = list1[2:] + list1[:2]

# Print the output

print(list1)

Posted 7-Mar-23 0:16am

sam82023

Updated 7-Mar-23 1:01am

v2

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Richard MacCutchan · Accepted Answer · 2023-03-07T00:31:00

Solution 1

You need to check each square value against its root number, something like:

Python

num = int(input("Enter number: "))
if i > 2:
    base = list1[i - 3]
    if base * base != num:
        print("{} is not a valid entry".format(num))
        break
list1.append(num)

Posted 7-Mar-23 0:31am

Richard MacCutchan