How can I create an index in a DBF file?

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I am using the C# dotnetdbf code (from github) to create, write and read dbf files.
It's great, except I cannot figure out how to create an index.

What I have tried:

There is a DBFField class which I use to set the field details (name, type, length) when I create a DBF. DBFField also has a 'byte indexFieldFlag' parameter which I tried setting to various values: 255 and 1 so far. But that does not seem make the field an index.

I think an indexed DBF field needs a .ntx file to define it.

Does anyone know how to create this please? I've looked through the dtnetdbf code and even though it looks like I can set an index field, it does not create a .ntx file.

Posted 1-Mar-23 22:07pm

Jackie Lloyd

Updated 2-Mar-23 11:51am

PIEBALDconsult

v3

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Richard Deeming 2-Mar-23 4:10am

Why not ask on the GitHub project? The authors of the project are the most likely people to be able to help you with their code.

Jackie Lloyd 2-Mar-23 4:26am

Thank you for the suggestion, I couldn't see a way to do that, but now see that I can add this as an issue - thanks for making me look again!

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RickZeeland · Answer 1 · 2023-03-02T07:46:00

Solution 1

Could not find any C# code, but you could have a look at:
TDBF, your free, open source, Delphi database engine! | Jon L. Aasenden[^]
It supports DBase indexes and can be used with the free Lazarus IDE, see:
Lazarus Tdbf Tutorial - Lazarus wiki[^]

Posted 2-Mar-23 7:46am

RickZeeland