Do not understand where %n

Question

0.00/5 (No votes)

See more:

int main() {
 unsigned long n;
 int c;
 printf( "Nhap n: " );
 scanf( "%lu%n", &n,&c );

What I have tried:

when I enter the value n = 4321, c is 4. Why is that, hope everyone can answer my question?

Posted 5-Jan-23 5:24am

Updated 5-Jan-23 5:54am

2 solutions

Add a Solution

Treat my content as plain text, not as HTML

…

Sign in to your account

Download, Vote, Comment, Publish.

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

OriginalGriff · Answer 1 · 2023-01-05T05:50:00

Because you told it to:
What is use of %n in printf() ? - GeeksforGeeks[^]
Since n has four digits, the value of c is set to 4.

Posted 5-Jan-23 5:50am

Richard MacCutchan · Answer 2 · 2023-01-05T05:54:00

Because, as described in the documentation at scanf Type Field Characters | Microsoft Learn[^], the n type code returns the number of characters read.

Posted 5-Jan-23 5:54am