C program to find even numbers

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i have a homework from an input of "2 3 5 -2 20 0 " till we meet 0 to find all even numbers. I wrote :

#include <stdio.h>

int main()
{
    int i, n;
  
    scanf("%d", &n);

    printf("I found %d even numbers \n", n);

    for(i=1; i<=n; i++)
    {
        
        if(i%2 == 0)
        {
            printf("%d\n", i);
        }
    }

    return 0;
}

when i print it finds there are 2 even numbers . i think i dont recognize the negative number . how can i correct that?

What I have tried:

.........................................

Posted 20-Nov-22 0:23am

Bogdan Alexandru Oct2022

Updated 20-Nov-22 11:02am

v2

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Richard MacCutchan 20-Nov-22 8:27am

Because you are printing the message before you test any of the numbers.

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Graeme_Grant · Answer 1 · 2022-11-20T00:39:00

Solution 1

When doing the test, use the abs function to make sure the value tested is a positive value. Here is more information on it: C library function - abs()[^]

Posted 20-Nov-22 0:39am

Graeme_Grant

Comments

Bogdan Alexandru Oct2022 20-Nov-22 7:10am

can u tell me how to write it pls?

0x01AA 20-Nov-22 7:16am

Modulo is defined also for negative numbers, I'm sure you know that. The 'for' is more the problem I think.

Graeme_Grant 20-Nov-22 7:17am

Yes, am aware.

OriginalGriff · Answer 2 · 2022-11-20T00:55:00

To add to what Graeme has said, the simplest solution is to ignore all the odd ones.
Instead of starting your loop at 1 and increasing it by 1, start it at 2 and increase it by 2:

C

for (int i = 2; i <= n; i += 2)
   ...

Since all the even number are multiples of two, why look at the intervening numbers at all?

CPallini · Answer 3 · 2022-11-20T05:36:00

Quote:
when i print it finds there are 2 even numbers

because your program just prints the first integer of the input sequence.

As matter of fact, if you feed it with the input sequence

3 19 27 42

it then prints

I found 3 even numbers

As it stands, your program is completely broken. You're given an input sequence that you must entirely process (well, you must process it until you find 0).

Try the following approach:

define a counter of even numbers, say even_count and initialise it with 0.
read an integer, say n from the input sequence (use scanf).
if n==0 the print the value of the even_counter and exit the program
here n is non-zero, check for its parity: if n is even the increment the even_count
goto point 2

merano99 · Answer 4 · 2022-11-20T11:02:00

Solution 4

Quote:
input of "2 3 5 -2 20 0 " till we meet 0

1. the result is output without searching an array
2. where is the array and why is n read in?
3. why is the index searched instead of the elements of an array?
Note: Even without abs() the result is 2,-2,20 - "I found 3 even numbers".

Posted 20-Nov-22 11:02am

merano99

Updated 20-Nov-22 11:04am

v2

C program to find even numbers

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