Fatal error: uncaught mysqli_SQL_exception: unknown column 'gender_detail' in 'field list'

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<?php	

include 'db_connection.php';


$fname = $_REQUEST['fname'];


$Lname = $_REQUEST['Lname'];


$Mname=$_REQUEST['Mname'];

$fathername= $_REQUEST['fathername'];


$address= $_REQUEST['address'];

$gender= $_REQUEST['gender'];



$sql ="INSERT INTO  form (first_name, last_name, mother_name, father_name, address_detail, gender_detail ) VALUES ('".$fname."', '".$Lname."', '".$Mname."', '".$fathername."', '".$address."', '".$gender."' )";

if ($conn->query ($sql) == TRUE) {
echo "New record created successfully";
} else {
echo "Error: " . $sql . "<br>" . $conn->error;
}

$conn->close();
	
	
?>

What I have tried:

doesn't seem to do with it....
Please answer as fast as you can.

Posted 10-Nov-22 20:13pm

Rebics Copy

Updated 10-Nov-22 21:10pm

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Member 15627495 11-Nov-22 2:18am

hello !

where is

$conn = mysqli->open(..,..?..?..);

if you don't use a function on $_REQUEST, it's just a reallocation of the value for nothing, it's useless the way you do.

$var_for_nothing = $_request['first_var'];

you're making 2 vars for 1 value. it's a problem.
$_REQUEST is an array, with vars in, already in memory stamp.
about gender_detail : if it's a boolean, you have to integrate this value without escaping characters, so 'no quote' 1 or 0 will pass.
the db engine wait for a 'boolean' and you send a 'string'. so an error is return.

CHill60 28-Mar-23 9:58am

Solution 1 is incorrect. Your database table does not have a column called gender_detail - check the spelling

2 solutions

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OriginalGriff · Answer 1 · 2022-11-10T21:10:00

Do not do it like that! Never concatenate strings to build a SQL command. It leaves you wide open to accidental or deliberate SQL Injection attack which can destroy your entire database. Always use Parameterized queries instead.

When you concatenate strings, you cause problems because SQL receives commands like:

SQL

SELECT * FROM MyTable WHERE StreetAddress = 'Baker's Wood'

The quote the user added terminates the string as far as SQL is concerned and you get problems. But it could be worse. If I come along and type this instead: "x';DROP TABLE MyTable;--" Then SQL receives a very different command:

SQL

SELECT * FROM MyTable WHERE StreetAddress = 'x';DROP TABLE MyTable;--'

Which SQL sees as three separate commands:

SQL

SELECT * FROM MyTable WHERE StreetAddress = 'x';

A perfectly valid SELECT

SQL

DROP TABLE MyTable;

A perfectly valid "delete the table" command

SQL

--'

And everything else is a comment.
So it does: selects any matching rows, deletes the table from the DB, and ignores anything else.

So ALWAYS use parameterized queries! Or be prepared to restore your DB from backup frequently. You do take backups regularly, don't you?

Member 15627495 · Answer 2 · 2022-11-10T20:36:00

Solution 1

using a 'boolean' for gender :

$sql ="INSERT INTO  form (first_name, last_name, mother_name, father_name, address_detail, gender_detail ) VALUES ('".$fname."', '".$Lname."', '".$Mname."', '".$fathername."', '".$address."',$gender)";

Posted 10-Nov-22 20:36pm

Member 15627495

Fatal error: uncaught mysqli_SQL_exception: unknown column 'gender_detail' in 'field list'

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Solution 2

Solution 1

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Fatal error: uncaught mysqli_SQL_exception: unknown column 'gender_detail' in 'field list'

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Solution 2

Solution 1

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