Click here to Skip to main content
15,881,248 members
Please Sign up or sign in to vote.
0.00/5 (No votes)
See more:
As the title mentioned, I have to remove adjacent duplicates in linked list such that if input is 'google', output should be 'le'. I'm supposed to code it in C. I've written 70% of the code, except that I don't know how to continuously loop till all adjacent duplicates are removed. I'm removing adjacent duplicates in remove_adjacent_duplicates() function, and since I don't know how to put terminating condition in loop, I've merely used if-else loop. But my code in remove_adjacent_duplicates() function might contain mistakes, so please rectify it if any and please give solution to looping till all adjacent duplicates are removed. Here's my code-

What I have tried:

C
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

struct node //node creation
{
  char data;
  struct node *next;
};

void remove_adjacent_duplicates(struct node** head_ref)
{
    struct node* current = *head_ref; 
    struct node* cnext = NULL; //the one next to current one
    int flag=0;
    
    cnext = current->next; //storing next
    //printf("%c %c %d\n",current->data,cnext->data,flag);
    
    if(cnext->data==current->data)
        {
            flag=1;
            while(cnext->data==current->data)
            {
                cnext=cnext->next;
            }
            current=cnext;
            cnext = current->next; //storing next

        }
        
    else
        {
            current=current->next;
            cnext = current->next; //storing next
            
        }
    //printf("%c %c %d\n",current->data,cnext->data,flag);
    if(flag) *head_ref = current;
    
}

void push(struct node** head_ref, char new_data)
{
    struct node* new_node = (struct node*)malloc(sizeof(struct node));
    new_node->data = new_data;
    new_node->next = *head_ref;
    *head_ref = new_node;
}


void printList(struct node* head)
{
    if (head == NULL)
    {
        printf("NULL\n\n");
        return;
    }
    
    printf("%c->",head->data);
    printList(head->next);
}

int main()
{
    char s[100];
    int i;
    struct node* a = NULL;
    
    printf("Enter string: ");
    scanf("%s",s);
    
    for(i=strlen(s)-1;i>-1;i--){
        push(&a, s[i]); //last in first out, so in reverse g is last but first to come out
    }

    printf("\nConverting string to linked list: \n");
    printList(a);

    
    //printf("%c",current->data); prints first letter of a 
    remove_adjacent_duplicates(&a);
    
    printList(a);


    return 0;
}
Posted
Updated 6-Nov-22 6:50am

1 solution

Use a true false flag. At the beginning of each search for duplicates, set it equal to 'false'. Whenever you find a duplicate, set it to 'true'. At the end of each loop if the value is still 'false', then you did not replace any duplicates. If it is still 'true' you did do some replacements, so you need to keep searching.
 
Share this answer
 

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)



CodeProject, 20 Bay Street, 11th Floor Toronto, Ontario, Canada M5J 2N8 +1 (416) 849-8900