How I extract a exact keys of a print?

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I have the next code

for elem in root:
    for nodo in root.iterfind(".//*[@type_id='1']"):
        print(nodo.attrib)

What I have tried:

With that code the show me this ( it is only a part of the result):

{'id': '1372839298', 'event_id': '3', 'type_id': '1', 'period_id': '1', 'min': '0', 'sec': '1', 'player_id': '37572', 'team_id': '43', 'outcome': '1', 'x': '50.1', 'y': '50.0', 'timestamp': '2011-08-21T16:00:40.179', 'last_modified': '2011-08-21T16:00:41'}
{'id': '978322590', 'event_id': '4', 'type_id': '1', 'period_id': '1', 'min': '0', 'sec': '2', 'player_id': '20664', 'team_id': '43', 'outcome': '1', 'x': '48.2', 'y': '49.1', 'timestamp': '2011-08-21T16:00:41.585', 'last_modified': '2011-08-21T16:00:44'}
{'id': '1962550717', 'event_id': '7', 'type_id': '1', 'period_id': '1', 'min': '0', 'sec': '19', 'player_id': '42593', 'team_id': '43', 'outcome': '0', 'x': '27.8', 'y': '100.0', 'timestamp': '2011-08-21T16:00:58.445', 'last_modified': '2011-08-21T16:01:01'}
{'id': '1886599927', 'event_id': '5', 'type_id': '1', 'period_id': '1', 'min': '0', 'sec': '23', 'player_id': '27696', 'team_id': '30', 'outcome': '1', 'x': '50.9', 'y': '20.0', 'timestamp': '2011-08-21T16:01:02.466', 'last_modified': '2011-08-21T16:01:17'}

and it is okey, previously I created empty list and now I want to extract the values of period_id, min, sec, player_id and team_id and make a table. I know how to filter ( previous code ) but I don t know how to extract this specific variables into a list

my try:

for i, v in enumerate(mydic):
    for j in v:
        if j == 'team_id':
            equipo.append(mydic[i][j])
        elif j == 'sec':
            segundo.append(mydic[i][j])

print(equipo)
print(segundo)

Posted 31-Oct-22 4:31am

David Vazquez Bande

Updated 31-Oct-22 6:28am

v5

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Richard MacCutchan · Answer 1 · 2022-10-31T05:04:00

Solution 1

You have all the information in the printed results. The nodo.attrib is a standard Python dictionary of all the attributes of the node. See Built-in Types — Python 3.11.0 documentation[^] for the methods of dictionaries.

[edit]
Starting with a list of all your dictionary items, something like:

Python

stuff = [{'id': '1372839298', 'event_id': '3', 'type_id': '1', 'period_id': '1', 'min': '0', 'sec': '1', 'player_id': '37572', 'team_id': '43', 'outcome': '1', 'x': '50.1', 'y': '50.0', 'timestamp': '2011-08-21T16:00:40.179', 'last_modified': '2011-08-21T16:00:41'},
         {'id': '978322590', 'event_id': '4', 'type_id': '1', 'period_id': '1', 'min': '0', 'sec': '2', 'player_id': '20664', 'team_id': '43', 'outcome': '1', 'x': '48.2', 'y': '49.1', 'timestamp': '2011-08-21T16:00:41.585', 'last_modified': '2011-08-21T16:00:44'},
         {'id': '1962550717', 'event_id': '7', 'type_id': '1', 'period_id': '1', 'min': '0', 'sec': '19', 'player_id': '42593', 'team_id': '43', 'outcom': '1', 'x': '48.2', 'y': '49.1', 'timestamp': '2011-08-21T16:00:41.585', 'last_modified': '2011-08-21T16:00:44'} ]
newlist = []
keys = [ 'period_id', 'min', 'sec', 'player_id', 'team_id' ]
for d in range(len(keys)):
    newlist.append([])
for dicts in stuff:
    for k in range(len(keys)):
        newlist[k].append(dicts[keys[k]])
print(newlist)

[/edit]

Posted 31-Oct-22 5:04am

Richard MacCutchan

Updated 31-Oct-22 5:45am

v2

Comments

David Vazquez Bande 31-Oct-22 11:06am

yeah, I know that I have the results but I need to add this results to a empty list

Richard MacCutchan 31-Oct-22 11:09am

What exactly is the problem in copying those specific items to the new list?

David Vazquez Bande 31-Oct-22 11:10am

it a list more longer than this, it is only a extract for seeing a example of the output

Richard MacCutchan 31-Oct-22 11:26am

Fine, but I still have no idea what your problem is. Please use the Improve question link above, and add complete details of what is not working.

David Vazquez Bande 31-Oct-22 11:27am

I need to extract the values of min, sec ... and put it in different list. Like create a csv

Richard MacCutchan 31-Oct-22 11:45am

See my updated solution.

David Vazquez Bande 31-Oct-22 11:51am

the code show me this error

TypeError: string indices must be integers

in this line

newlist[k].append(dicts[keys[k]])

Richard MacCutchan 31-Oct-22 11:57am

You must have used different code from what I posted, so you need to show it.

David Vazquez Bande 31-Oct-22 12:26pm

okey I try something different but I have a problem.

In my 1º result ( your stuff ) I don t have "," after every line and it is easy put a "," when you have 3 lines but it is impossible when you have 10000 lines

Richard MacCutchan 31-Oct-22 12:30pm

Then you will have to modify the code you use to extract this data from your XML. Just using a print statement is obviously not the best way. The code I gave you was just a simple example to show how you could build a list of the values you are trying to extract.

David Vazquez Bande 31-Oct-22 12:33pm

what is the way to put a comma after each line or modify the result? because I only have the result without commas as you can see .

Richard MacCutchan 31-Oct-22 12:39pm

Something like:

newlist = []for elem in root:
    for nodo in root.iterfind(".//*[@type_id='1']"):        newlist.append(nodo.attrib)

Note, that with the amount of data you have you may run into memory problems so you may need to think about extracting the individual fields for each attribute list and writing them to a file.

David Vazquez Bande 31-Oct-22 12:29pm

and yes, my code work, but I need to put a comma in every line