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I have total score for 2 years which is 2022 and 2023 with same name. My problems is the total score calculated all the year.

What I have tried:

$sectionb_total_score = 0;
	$Year = date('Y');
	$mySQL2 = 'SELECT COUNT( as TotalID, SUM(A.total_score) as TotalScore, A.year_assessment FROM assessment_technical A INNER JOIN assessment_year B ON A.assessment_year_id = WHERE A.year_assessment = B.year_assessment AND A.staff_id =' .$data['staff_id'] ;
	$result2 = mysql_query($mySQL2);
	if ($result2){
		if (mysql_num_rows($result2) > 0){
		$row2 = mysql_fetch_assoc($result2);
		$sectionb_total_score = $row2['TotalScore'] / $row2['TotalID'];
Updated 28-Aug-22 19:02pm

1 solution

Try using a GROUP BY clause: SQL GROUP BY Statement[^]
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OriginalGriff 30-Aug-22 1:02am    
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