C# replace shortcode with partialview in ASP .NET

Question

0.00/5 (No votes)

See more:

I have defined few shortCode in Database. When i am displaying in view, ShortCode not replacing with the PartalView defined in the Dictionary.

In Database i am creating a field Description. There i am storing HTML text along with Few Short code. When i display Description in view. I want the short Code to replace with Partial view. Like we do in WordPress/Joomla. In Database i define ShortCode. I want that sortCode replaced with PartialView.

This is the message i am getting on the screen microsoft.AspNetCore.Mvc.ViewFeatures.Buffers.ViewBuffer

What I have tried:

@{
	var input = "<div>Hello This is Same</div><div>{partv _AllPages}</div><div>Some Content</div><div>{partv _AllPost}</div>";
	var replacements = new Dictionary<string, string>
	{ 
		{ "{partv _AllPages}", Html.Partial("_AllPages").ToString()},
		{ "{partv _AllPost}", Html.Partial("_AllPost").ToString()}
	};
	var output = replacements.Aggregate(input, (current, replacement) => current.Replace(replacement.Key, replacement.Value));
}
@Html.Raw(HttpUtility.HtmlDecode(output))

Posted 9-Aug-22 6:30am

Member 12953926

Updated 9-Aug-22 7:13am

Add a Solution

1 solution

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Richard Deeming · Accepted Answer · 2022-08-09T07:13:00

Solution 1

The Html.Partial method returns a ViewBuffer instance. That class does not override ToString, so the result of that method will be the full class name.

If you want to render the content to a string, you need to use the WriteTo method[^].

C#

var replacements = new Dictionary<string, IHtmlContent>
{
    ["{partv _AllPages}"] = Html.Partial("_AllPages"),
    ["{partv _AllPosts}"] = Html.Partial("_AllPosts"),
};

string output = input;
foreach (var pair in replacements)
{
    if (!output.Contains(pair.Key)) continue;
    
    string replacement;
    using (var writer = new StringWriter())
    {
        pair.Value.WriteTo(writer, HtmlEncoder.Default);
        replacement = writer.ToString();
    }
    
    output = output.Replace(pair.Key, replacement);
}

NB: Calling HttpUtility.HtmlDecode on the output is almost certainly the wrong thing to do.

I suspect you might be better served using something like this:
Back to Basics: Rendering Razor Views to String in ASP.NET Core - Rick Strahl's Web Log[^]

Posted 9-Aug-22 7:13am

Richard Deeming

Updated 10-Aug-22 1:21am

v3

Comments

Member 12953926 10-Aug-22 2:59am

hi thanks for the solution. I have tried it. It gives error. Use of unassigned local variable 'replacement'. Please help

Here what i tried:

@{
var input = "Hello This is Same{partv _AllPages}Some Content{partv _AllPost}";
var replacements = new Dictionary<string,ihtmlcontent>
{
["{partv _AllPages}"] = Html.Partial("_AllPages"),
["{partv _AllPosts}"] = Html.Partial("_AllPosts"),
};
string output = input;
foreach (var pair in replacements)
{
if (!output.Contains(pair.Key)) continue;

string replacement;
using (var writer = new StringWriter())
{
pair.Value.WriteTo(writer, HtmlEncoder.Default);
}

output = output.Replace(pair.Key, replacement);
}
}
@Html.Raw(HttpUtility.HtmlDecode(output))

Richard Deeming 10-Aug-22 7:21am

Sorry, I missed the replacement = writer.ToString(); line - I've updated my answer.

Member 12953926 10-Aug-22 12:36pm

Thanks a Lot. It worked.

Member 12953926 2-Sep-22 7:01am

hi Richard, The above scrip work perfects. Can we cut-shot the script? Because there will be around 200+ partial view in my project. Is there any better way to do?

Member 12953926 13-Dec-22 6:02am

hi Richard. There is one issue..
in the above script - var input = "Hello This is Same{partv _AllPages}Some Content{partv _AllPost}";
i have removed one partv and its now
var input = "Hello This is Same Some Content";

In the result its calling Html.Partial("_AllPages") and Html.Partial("_AllPosts"). They should be get replaced if its exists in input.

This time in Html.Partial("_AllPages") and Html.Partial("_AllPosts") i have added C# code. Please help.

Richard Deeming 13-Dec-22 6:25am

Based on your comment, you've removed all partial view references from your string. I don't understand why you'd expect the code to insert anything in that string.

Member 12953926 13-Dec-22 7:20am

Actually i want to define the Partial View dynamically(without Ajax). Like short code. If the short code exists in the description,, then that should be replaced with the Partial view. Any thoughts on this ?

Richard Deeming 13-Dec-22 7:21am

That's exactly what my answer did. Which you accepted back in September. What has changed in the last three months?

Member 12953926 13-Dec-22 7:46am

Its works with Plain HTML code.

Now the situation is with C# code.

For Example:
Page 1 description:
var input = "Hello This is Same{partv _AllPages}Some Content{partv _AllPost}";

Page 2 description:
var input = "Hello This is Same{partv _AllPages}Some Content";

Html.Partial("_AllPosts") ==> having C# code for getting the dynamic data.

Output: Now if I load Page 2 in browser, control is going to Html.Partial("_AllPosts") partial view page(_AllPosts.cshtml). Not sure why. For Page 2 it should not go. Because the short code is not present in description column.

Richard Deeming 13-Dec-22 9:57am

I've obviously not had enough coffee today - that makes absolutely no sense to me.

If you want to insert the result of C# code into a string, rather than executing a partial view, then you can use string interpolation:

string result = $"The answer is: {7 * 6}";

Or you can use composite formatting:

string result = string.Format("The answer is: {0}", 7 * 6);

But your question was about inserting a partial view into the string, which is what my answer does.

Member 12953926 29-Jan-24 9:23am

hi Richard,
Thanks for the above suggestions. Its working perfect for windows virtual machines. very recent i have noticed In linux VM when i name a partial view with few names like _CTS.cshtml,_Cpl_Scrn.cshtml,_CTC.cshtml is not working. Should i follow any naming convention when i create partial view for Linux machines ?