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def task_5(x):
y=1
for i in range(0, 21, 5):
if i == 0: continue
y = y + ((x ** i) / i) if (i % 2) == 0 else y - ((x**i)/ i)
print(y/2)

What I have tried:

Function task5()
Dim x As Single, y As Single
x = 1
y = 1
'for i to


' i dont know how to write a vba code

End Function
Posted
Updated 30-Jun-22 1:27am
Comments
Dave Kreskowiak 30-Jun-22 10:36am    
It's impossible for anyone to teach you a language in a few forum posts.

1 solution

We aren't here to teach you a whole language - we only have a tiny text box to work in, and you can buy whole books with hundreds if not thousands of pages on the subject.

And we are not a code conversion service: we are not here to translate code for you.
Even if we did, what you would end up with would not be "good code" in the target language – they are based on very different frameworks, and what makes something work in one language does not always "translate" directly into another.
So what you end up with is very poor code, that is difficult if not impossible to maintain, that can’t be upgraded nicely, and that will cause you immense headaches if the original is changed. And it'll be a nightmare to debug if it doesn’t work "straight out of the box".
Instead, use the source code as a specification for a new app written in and for the target language / framework and write it from scratch using the original as a "template". You will get a much, much better result that will save you a lot of time in the long run.
 
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