To detect whether an internal square matrix has its corners are the same characters.

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Python

Matrix

I have tried giving input for a 2X2 matrix.

   0  1
0  x  x
1  y  x

But the output still is "Matrix not allowed" according to my code, whereas for this input it should just run well. Please let me know where I am going wrong.

What I have tried:

This is my code

import numpy as np
import pandas as pd

n=int(input('Give value of n size of the matrix : '))

arr=np.zeros([n,n])
df=pd.DataFrame(arr)
print(df)
rows = n
col = n
num=rows*col

b=input('First character: ')

d=input('Second charater: ')

i=1
while i<=num:
              
        e=int(input('enter row no.:'))
        f=int(input('enter col no.:'))
        choice = input('Which character do you want to enter : ')
        if choice!=b and choice!=d:
          print('Enter correct charcters')
          choice = input('Which character do you want to enter : ')

        if df.iat[e,f]!=0:
            print('position is filled! give different coordinates')
            e=int(input('enter row no.:'))
            f=int(input('enter col no.:'))
        df.iat[e,f]=choice
        print(df)

        
        i+=1



for a in range(2,n+1):
  for j in range(0,n-a+1):
    if df.iat[j,j]==df.iat[j,j+a-1] and df.iat[j,j]==df.iat[j+a-1,j] and df.iat[j,j]==df.iat[j+a-1,j+a-1]:
      z=1
    if z==1:
      print('matrix not allowed')