How do I add octal to integer

Question

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Bash

shopt -s dotglob nullglob
shopt -s globstar 
for pathname in CWFiles/**/*.txt; do 
   [ ! -f "pathname" ] && continue

   while read -r line
   do 
      result=(( "$result" + "$pathname" ))
      echo $result

   done < "pathname" 
done

What I have tried:

I'm trying to calculate the total number >> result by adding each line to result
the problem is "pathname" can be sometimes a number with leading zeros.
the shell does not add octal number to integer as my error massage says.
how do I come around this problem even after trying $((10#"$pathname")) it didn't work.

Posted 19-Jan-22 7:58am

mohamed abubeker

Updated 19-Jan-22 11:19am

k5054

v2

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k5054 · Answer 1 · 2022-01-19T11:19:00

What you have posted here make no sense. As written, this line

Bash

result=(( "$result" + "$pathname" ))

, seems to be trying to accumulate something to result, but since you have

Bash

for pathname in CWFiles/**/*.txt

then pathname will hold a value something like CWFiles/foo/bar.txt. Clearly, that's not a number, so the attempt at addition is not going to work. It looks like you're trying to use integer math in a bash script, so you might want to use let or declare expressions instead. Incidentally, let expressions do octal math as expected:

Bash

[k5054@localhost tmp]$ let result=10
[k5054@localhost tmp]$ echo $result
10
[k5054@localhost tmp]$ let result+=10
[k5054@localhost tmp]$ echo $result
20
[k5054@localhost tmp]$ let result+=010  # octal addition
[k5054@localhost tmp]$ echo $result
28[k5054@localhost tmp]$

Maybe you want something more like:

Bash

shopt -s dotglob nullglob
shopt -s globstar
let result=0 
for pathname in CWFiles/**/*.txt; do
   [ ! -f "$pathname" ] && continue 

   while read -r line
   do 
      let result+=$line
      echo $result

   done < "$pathname" 
done