How to find a particular value in a string array and return those values?

Question

1.00/5 (1 vote)

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For ex: The user inputs "n" designations and we check which of them is a sales designation and display those.

Input:
3 // no. of designations
SalesManager
SalesExecutive
HRManager

Output:
Designations in Sales dept are:2
SalesManager
SalesExecutive

What I have tried:

I don't understand what to do, I took the array from the user:

public class sales {
    public static void main(String[] args) {
        Scanner sc=new Scanner(System.in);
        int n=sc.nextInt();
        String arr[]=new String[n];
        if(n>0){
            for(int i=0;i<n;i++){
                arr[i]=sc.nextLine();
            }
            
        }
        else{
            System.out.println("INVALID INPUT");
        }
    }
    
}

Posted 11-Jan-22 23:31pm

Sourabh Jambale

Updated 12-Jan-22 0:48am

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3 solutions

Solution 1

See here: Java String.equals() Method[^]

Posted 12-Jan-22 0:05am

OriginalGriff

Comments

Sourabh Jambale 12-Jan-22 6:06am

But we don't want to compare strings here, we want to input some strings and then check if those strings contain the word "Sales" and print those values.

OriginalGriff 12-Jan-22 6:31am

And what have you tried to do that so far?

Sourabh Jambale 12-Jan-22 6:36am

I did

if (Arrays.stream(arr).anyMatch("sales"::equals)) {
                    System.out.println(arr[i]);
                }

but it doesn't show any output.

OriginalGriff 12-Jan-22 6:52am

I'm sure it does: it gives the error "cannot find symbol" for "i" as it has no idea what you are trying to do, and you couldn't fulfil you homework requirements if it did, and you have no way to find *which* string it triggered on!

Have you considered look at the Java String contains() Method[^]

Solution 2

Here is the Tip for you. Some of the search complexities have been ignored intentionally.

* Build a Class "Designation"
* Designation Class should have Two Attributes. DesignationType and DesignationName
* Take Number of Designations as Input in N
* ArrayList<Designation> designationList = new ArrayList<Designation>()
* For each I in N
*    Designation design = new Designation()
*    Set design.DesignationName = Take Input
*    Set design.DesignationType = Take Input
*    designationList.Add(design)
* End For
* Input DesignationType into searchType
* For Each K in N
*     design = designationList(K)
*     IF (design.DesignationType == searchType)
*         Print design.DesignationName
*     End If
* End For
* End

Posted 12-Jan-22 0:27am

_Asif_

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M Imran Ansari · Accepted Answer · 2022-01-12T00:48:00

Solution 3

string designation = "Sales";
int counter = 0;
string[] result = new string[5];

for (int j = 0; j < answer.Length; j++)
{
	if (answer[j].StartsWith(designation))
	{
		result[counter] = answer[j];
		counter++;
	}
}

System.out.println("Designations in Sales dept are: " + counter + "");
for (int i = 0; i < counter; i++)
{
	System.out.println(result[i]);
}

Posted 12-Jan-22 0:48am

M Imran Ansari

Updated 12-Jan-22 0:51am

v2

Comments

Sourabh Jambale 12-Jan-22 9:02am

What is the "answer" variable here?

M Imran Ansari 12-Jan-22 10:07am

Source array, where values exists ie, SalesManager, SalesExecutive etc.

Sourabh Jambale 13-Jan-22 2:18am

Thank you so much for the answer. But how can we avoid the negativesArraysize exception error in this code? We want to return "Invalid input" when we enter a negative value for "n" which is the array size. Here's my code:

String designation = "Sales";
        int counter = 0, n;
        Scanner sc = new Scanner(System.in);
        n = sc.nextInt();
        String[] result = new String[n];
        if (n > 0) {
            for (int i = 0; i < n; i++) {
                result[i] = sc.next();
            }
            for (int j = 0; j < result.length; j++) {
                if (result[j].startsWith(designation)) {
                    result[counter] = result[j];
                    counter++;
                }
                
            }
            if(counter>0){
                System.out.println("Designations in Sales Department " + counter );
                
            }
            else if(counter==0){
                System.out.println("No designations in Sales department ");
            }
           
            for (int i = 0; i < counter; i++) {
                System.out.println(result[i]);
            }
        }
        else{
            System.out.println("INVALID INPUT");
        }

M Imran Ansari 13-Jan-22 4:41am

String designation = "Sales";
int counter = 0, n;
Scanner sc = new Scanner(System.in);
n = sc.nextInt();
String[] result; // Declare the array
if (n > 0)
{
result = new String[n]; // Initialize here
....
..
}
else
{
System.out.println("INVALID INPUT");
}

Sourabh Jambale 13-Jan-22 7:58am

Thank you!