Java servlet 404 the web page does not return result

Question

1.00/5 (1 vote)

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The web page that sends parameters to servlet does not return result instead

404 appears

it has been deployed and web xml has the details

The web page is

<html>
    <head>
        <title>Wow</title>        
    </head>
    <body>
        <form  name ="wow" method="GET" action="ThatWas">
            Name : <input type="text" name="name">                        
            <input type="submit" value="That">                        
        </form>        
    </body>
</html>

Servlet

import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

public class ThatWas extends HttpServlet 
{    
    protected void processRequest(HttpServletRequest request, HttpServletResponse response)
            throws ServletException, IOException
{
        response.setContentType("text/html;charset=UTF-8");
        try (PrintWriter out = response.getWriter()) {
            String name = request.getParameter("name");            
            out.println("<!DOCTYPE html>");
            out.println("<html>");
            out.println("<head>");
            out.println("<title>Servlet ThatWas</title>");            
            out.println("</head>");
            out.println("<body>");
            out.println("That was good " + name + request.getContextPath());            
            out.println("</body>");
            out.println("</html>");
        }
}

and the xml is

<?xml version="1.0" encoding="UTF-8"?>
<web-app id="file-upload" version="2.4" xmlns="http://java.sun.com/xml/ns/j2ee" 
         xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
	 xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee 
         http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">	       
        
        <servlet>
            <servlet-name>ThatWas</servlet-name>
            <servlet-class>ThatWas</servlet-class>
       </servlet>
    
        <servlet-mapping>
		<servlet-name>ThatWas</servlet-name>
                <url-pattern>/ThatWas</url-pattern>
	</servlet-mapping>
        
        <welcome-file-list>
            <welcome-file>That.html</welcome-file>
        </welcome-file-list>
</web-app>

What I have tried:

Code changes and research with internet and books

Posted 12-Dec-21 22:54pm

four systems

Updated 27-Dec-21 22:59pm

v2

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Comments

Richard MacCutchan 13-Dec-21 5:08am

You cannot expect anyone here to guess what your secret code is doing.

1 solution

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four systems · Accepted Answer · 2021-12-27T22:59:00

That code works

import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

public class ThatWas extends HttpServlet 
{    
    protected void processRequest(HttpServletRequest request, HttpServletResponse response)
            throws ServletException, IOException
{
        response.setContentType("text/html;charset=UTF-8");
        try (PrintWriter out = response.getWriter()) {
            String name = request.getParameter("name");            
            out.println("<!DOCTYPE html>");
            out.println("<html>");
            out.println("<head>");
            out.println("<title>Servlet ThatWas</title>");            
            out.println("</head>");
            out.println("<body>");
            out.println("That was good " + name );            
            out.println("</body>");
            out.println("</html>");
        }
}