How do I end the code

Question

1.00/5 (1 vote)

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I am using python 3

Python

import sys
while True:
   answer = input('Do you want to continue?:')
   if answer.lower().startswith("y"):
      print("ok, carry on then")
   elif answer.lower().startswith("n"):
       sys.exit()
x = str(input("Enter A or B for a Trick Or a Treat!: "))
if x == 'a':
    print("treat")
else:
    print("trick")

It out puts "do you wish to continue" upon pressing yes it keeps repeating instead of asking press a or b for a trick or a treat

What I have tried:

I tried breaks and randoms but they both dont work

Posted 26-Oct-21 10:45am

Joseph Diblasi

Updated 26-Oct-21 21:42pm

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phil.o · Answer 1 · 2021-10-26T10:59:00

Python is indentation-sensitive, so from the line x = str(... this part does not belong to the while loop.
Try

Python

import sys
while True:
   answer = input('Do you want to continue?:')
   if answer.lower().startswith("y"):
      print("ok, carry on then")
   elif answer.lower().startswith("n"):
      sys.exit() #warning: indentation here was not correct (4 spaces instead of 3)
   x = str(input("Enter A or B for a Trick Or a Treat!: "))
   if x == 'a':
      print("treat") #idem here
   else:
      print("trick") #idem here

Python Indentation[^]

Mike Hankey · Answer 2 · 2021-10-26T11:04:00

Solution 2

Not real uip on Python but try this

Python

import sys
while True:
   answer = input('Do you want to continue?:')
   if answer.lower().startswith("y"):
      print("ok, carry on then")
      x = str(input("Enter A or B for a Trick Or a Treat!: "))
      if x == 'a':
          print("treat")
      else:
          print("trick"
   elif answer.lower().startswith("n"):
       sys.exit()
)

Posted 26-Oct-21 11:04am

Mike Hankey

Comments

Joseph Diblasi 26-Oct-21 17:15pm

File "main.py", line 11
elif answer.lower().startswith("n")
^
IndentationError: unindent does not match any outer indentation level

Joseph Diblasi 26-Oct-21 17:16pm

I wanna make it so it changes trick or treat on a so it can be trick once treat next and it asks if u wanna continue

Mike Hankey 26-Oct-21 17:29pm

Set a flag and check, if set answers trick or if false answers treat and updarte flag.

Joseph Diblasi 26-Oct-21 17:50pm

?

Richard MacCutchan · Answer 3 · 2021-10-26T21:42:00

Try this slightly simpler option, which does not need sys.exit():

Python

while True:
    x = str(input("Enter A or B for a Trick Or a Treat!: "))
    if x.lower().startswith("a"):
        print("treat")
    else:
        print("trick")
    answer = input('Do you want to continue?:')
    if answer.lower().startswith("y"):
        print("ok, carry on then")
    else:
        break # terminate the while loop

How do I end the code

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