How can I escape "print("oops I'll try again")" only after using "if tries %6 == 0"?

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if tries %6 == 0:
        print("did you chose a word ?")
        input()
        lost = list
print("oops I will try again")
list .append(guess)
lost .remove(guess)

What I have tried:

i tried to use pass and continue

Posted 10-Sep-21 8:20am

Member 15331575

Updated 10-Sep-21 9:06am

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OriginalGriff · Accepted Answer · 2021-09-10T09:06:00

Python indentation is significant: it handles flow control by "grouping" lines of code together into "blocks" according to the same level of indentation. Stupid, I know - but I didn't design the thing.

So if you want the line only printed when tries % 6 == 0 then indent it to teh same level as the rest of the block:

        print("did you chose a word ?")
        input()
        lost = list
        print("oops I will try again")

If you want to only do it when the condition fails, then you need to add an else statement: Python Conditions[^]