Vba return multiple array results

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hello everybody. i drawn down below code. this is meant to return multiple split string parts in same row but different colmuns one beside other. however , even if i click and drag the function on close columns, it keeps returning the first array value only.

Function SCOMPONI(stringa As String) As Variant
Dim TAGLIA As Variant, Colonne As Integer, MATRICE() As String, i As Integer

TAGLIA = Split(Trim(stringa), " ")
Colonne = UBound(TAGLIA)

    ReDim MATRICE(0 To 0, 0 To Colonne)
    For i = 0 To Colonne
        MATRICE(0, i) = TAGLIA(i)
    Next
    
SCOMPONI = MATRICE
End Function

What I have tried:

i tried to explicit array sizes (0 to n) , and writing double circle brackets beside the array variable name [SCOMPONI() = MATRICE()]
but nothing
thanks

Posted 23-Jun-21 20:56pm

Mat 257

Updated 23-Jun-21 21:54pm

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Maciej Los 24-Jun-21 2:59am

Can you post input string and expected output?

Mat 257 24-Jun-21 3:28am

yes,
input "Basilico Biologico 107/21 10Sx Cella1 Gambo" in cell(1,1)

process: split string out " " delimiter

expected output:

Basilico range(1,2) Biologico range(1,3) 107/21 range(1,4) 10Sx range(1,5) Cella1 range(1,6) Gambo range(1,7)

Maciej Los 24-Jun-21 3:37am

There's embeded function in MS Excel. See: Split text into different columns with the Convert Text to Columns Wizard - Excel[^]
VBA: Range.TextToColumns method (Excel) | Microsoft Docs[^]

Mat 257 21-Feb-22 9:06am

thanks

Maciej Los 21-Feb-22 10:11am

You're very welcome :)

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Maciej Los · Accepted Answer · 2021-06-23T21:54:00

As i mentioned in the comment to the question there's no need to write custom function, because it has been written already: Range.TextToColumns method (Excel) | Microsoft Docs[^]

But if you want to return specific "word" from text, you can write a function like this:

VBA

Function SCOMPONI(stringa As String, Optional itemNo As Integer = 0) As Variant
        Dim matrice As Variant, retVal As Variant
        matrice = Split(Trim(stringa), " ")
        
        If itemNo < 0 Then itemNo = 0
        If itemNo > UBound(matrice) Then itemNo = UBound(matrice)
        
        retVal = matrice(itemNo)

        SCOMPONI = retVal
End Function

Usage:

B1 = SCOMPONI($A$1, 0)
C1 = SCOMPONI($A$1, 1)
D1 = SCOMPONI($A$1, 2)