How do I display the consonant letters from the user's input?

Question

1.00/5 (1 vote)

See more:

Using recursion, I need to display the consonant letters and the total number of consonant letters from the user's input. Thank you in advance.

What I have tried:

Python

a = input("Enter your string:")
print("Your string:", a.split())

def isCons(ch):
     
    ch = ch.upper()
 
    return not (ch == 'A' or ch == 'E' or
                ch == 'I' or ch == 'O' or
                ch == 'U') and ord(ch) >= 65 and ord(ch) <= 90
 
def totalCons(string, n):
     
    if n == 1:
        return isCons(string[0])
 
    return totalCons(string, n - 1) + isCons(string[n-1])
    
print(totalCons(a, len(a)))

Posted 20-Apr-21 20:18pm

lil_mint

Updated 21-Apr-21 0:21am

CPallini

v3

Add a Solution

4 solutions

Solution 1

Don't use recursion - it's not a suitable method for processing this kind of request, and it may cause your app to fail.

This is an iterative problem, that just requires a simple loop: nothing in the "structure" of s string of characters is recursive, unlike the definition of factorial for example:

f(N) = N <= 1 ? 1 : N * f(N - 1)

Where the function is defined in terms of the function.

Use a simple for loop instead. Remember, each time you call a function, you use stack space, and that is very limited. A long string will exhaust the stack space in a recursive solution, where the looping version needs almost no stack at all. When you stack runs out, your app crashes.

Posted 20-Apr-21 20:56pm

OriginalGriff

Comments

lil_mint 21-Apr-21 20:50pm

Thank you very much for the explanation. I did think for loop seems more ideal but my assignment was to use recursion. Again thank you.

Solution 2

Python

for letter in string:
    if letter not in 'aeiouAEIOU':
        print(letter, 'is a consonant')

Posted 20-Apr-21 21:42pm

Richard MacCutchan

Comments

CPallini 21-Apr-21 3:56am

That would classify '%' as a consonant.

Richard MacCutchan 21-Apr-21 4:08am

It is an over simplification, and OP is expected to consider all cases. Unfortunately few people seem capable of independent though these days.

Solution 4

I would rather search for letters I want.

Python

Consonant= "BCDFGHJKLMNPQRSTVWXZbcdfghjklmnpqrstvwxz"

and check each char from input against this string.

Quote:
Using recursion

In this case, recursion complicate things. It is easier to use a loop.

Posted 21-Apr-21 0:21am

Patrice T

Comments

lil_mint 21-Apr-21 20:52pm

Thank you. I also think for loop was more easier but my assignment was to use recursion. Thank you very much.

Add a Solution

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

CPallini · Accepted Answer · 2021-04-20T21:54:00

If you have to use recursion then, recursively building the string of consonants should do the trick

Python

a = input("Enter your string:")
print("Your string:", a.split())

def cons(ch):
    uch = ch.upper()
    if  ( ord(uch) >= 65 and ord(uch) <=90 and not ( uch in "AEIOU")):
        return ch
    return ''

def totalCons(string, n):
    if n == 1:
        return cons(string[0])
    return totalCons(string, n - 1) + cons(string[n-1])


totcons = totalCons(a, len(a))
print( totcons, len(totcons))

How do I display the consonant letters from the user's input?

4 solutions

Solution 1

Solution 2

Solution 3

Solution 4

Add your solution here

Preview 0

How do I display the consonant letters from the user's input?

4 solutions

Solution 1

Solution 2

Solution 3

Solution 4

Add your solution here

Preview 0

Existing Members

...or Join us