Why is it necesssary to first capitalize and then replace in Python?

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Write a function that capitalizes the first and fourth letters of a name
The output should be

-->
old_macdonald('macdonald') --> MacDonald

Python

def old_macdonald(name):
    a=name.capitalize()
    b=a[3].capitalize()
    c=a.replace(a[3],b,1)
    return c

The above code works fine.But the below one isnt working and i m not able to get why isnt it working

Python

def old_macdonald(name):
    a=name.replace(name[3],name[3].capitalize(),1)
    b=a.capitalize()
    return b

What I have tried:

I tried in second way,i didnt get why that code doesnt work

Posted 15-Apr-21 20:29pm

Pooja Ekbote

Updated 15-Apr-21 21:37pm

CPallini

v2

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markkuk · Answer 1 · 2021-04-15T21:23:00

Solution 1

According to the documentation[^] str.capitalize() does the following:

Return a copy of the string with its first character capitalized and the rest lowercased.

Your code line b=a.capitalize() undoes the changes done on the previous line.

Posted 15-Apr-21 21:23pm

markkuk

Comments

CPallini 16-Apr-21 3:38am

5.

CPallini · Answer 2 · 2021-04-15T21:37:00

Because the second call to capitalize removes the effect of the first one

Python

def old_macdonald(name):
    a=name.replace(name[3],name[3].capitalize(),1) # this makes the fourth character uppercase
    b=a.capitalize() # this makes the first character uppercase AND the fourh character Lowercase
    return b

See, for instance: string capitalize() in Python - GeeksforGeeks[^].