Why is there (reading.x) with the parenthesis? What does it mean?

Question

1.00/5 (1 vote)

See more:

onReadingChanged: {
accelerometerReading.xValue = (reading.x).toFixed(2);
accelerometerReading.yValue = (reading.y).toFixed(2);
accelerometerReading.zValue = (reading.z).toFixed(2);
}

What I have tried:

onReadingChanged: {
accelerometerReading.xValue = (reading.x).toFixed(2);
accelerometerReading.yValue = (reading.y).toFixed(2);
accelerometerReading.zValue = (reading.z).toFixed(2);
}

Posted 17-Feb-21 8:49am

jacobglaw

Updated 18-Feb-21 19:37pm

Add a Solution

Comments

20212a 17-Feb-21 14:53pm

No idea. What is this from?

Parenthesis are probably not required.

Member 15075381 17-Feb-21 18:00pm

Ok

[no name] 17-Feb-21 15:10pm

Did you try without paranthesis and you faced a problem then? If yes what problem?

KarstenK 18-Feb-21 10:29am

Not needed, but maybe a beginner, some code changes or for clarity.

3 solutions

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

OriginalGriff · Answer 1 · 2021-02-17T10:13:00

Solution 1

The brackets are probably not needed, but it's possible there was once a cast that required them - they just ensure that the dereference happens before the call to toFixed which would happen anyway!

Posted 17-Feb-21 10:13am

OriginalGriff

CPallini · Answer 2 · 2021-02-17T20:07:00

Solution 2

The brackets force the

C++

.x

evaluation to happen before the

C++

.toFixed(2)

one.

Note they are not needed because of the left-to-right associativity of the member access operator (.).
See C++ Operator Precedence - cppreference.com[^].

Posted 17-Feb-21 20:07pm

CPallini

steveb · Answer 3 · 2021-02-18T19:37:00

This does not look like C or C++.

C++

/*Illegal return value*/onReadingChanged:/*Illegal token and missing parameter list*/ {
accelerometerReading.xValue = (reading.x).toFixed(2);
accelerometerReading.yValue = (reading.y).toFixed(2);
accelerometerReading.zValue = (reading.z).toFixed(2);
}

I have no idea what syntax this is.