How do I determine week number form start date to end of today's week ?

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I need to determine weeknumbers from two dates.
I have a query in Access DB which looks like this. I am trying to achieve same query in Oracle. How do i do it? I have written a query but it does not seem like right.

IIf(Weekday([HiredDate])=7,[HiredDate],[HiredDate]-Weekday([HiredDate])) AS TrainingStart, 
Date()+6-Weekday(Date()) AS EndOfWeek, 
DateDiff("ww",[TrainingStart],[EndOfWeek]) AS WeekNumber,

What I have tried:

SELECT Name, HiredDate, 
(CASE WHEN (to_char(to_date(HiredDate), 'd') = 7) THEN HiredDate ELSE (HiredDate - to_char(to_date(HiredDate), 'd')) END) as StartDate, 
(CURRENT_DATE + (6 - to_char(to_date(CURRENT_DATE), 'd'))) as EndDate,
(To_Number(to_char(to_date((CURRENT_DATE + (6 - to_char(to_date(CURRENT_DATE), 'd')))),'WW')) - To_number(to_char(to_date((HiredDate - to_char(to_date(HiredDate), 'd'))),'WW')) +1) as WEEKNUMBER 
FROM employee;

Posted 25-Jul-19 17:43pm

istudent

Updated 25-Jul-19 22:29pm

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CHill60 26-Jul-19 4:14am

What are the results of your query. Do you have some sample data and expected results

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CHill60 · Answer 1 · 2019-07-25T22:30:00

To convert your Access query to Oracle …

Don't change the IIf - it also exists in Oracle - see IIF - Oracle Help Center[^]

Don't change the Weekday() - that function also exists in Oracle - see WeekDay - OracleDocs[^]

To replace DateDiff() you can just subtract one date from the other - see Data Types - OracleDocs[^]

To Replace the Date() function use either CURRENT_DATE[^] or SYSDATE[^]