UDP server sends 1st & client receive

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Hi,
I am building a little UDP server client app. in c++

In all the examples on the net that i saw, the server is 1st of all receives from the client and then sends
and the client 1st of all sends to the server and then receives from it.

I want the server to 1st of all send and the client to 1st of all receive.

The server will sends periodically a message and when the client is up it will receive it

Thanks!

dj

What I have tried:

I have built an echo server app. in which the server receives a message from a client a sends it back

Posted 30-Jun-19 20:56pm

dj4400

Updated 1-Jul-19 0:33am

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Gerry Schmitz · Answer 1 · 2019-07-01T00:34:00

Solution 1

The usual protocol is that the "master" sends first, and the slaves respond.

A slave never sends without being asked; it waits for a send request.

When the master starts, it polls available addresses (typically a subset within 1-31; 1-255; etc), with "address 0" for a general broadcast to all slaves listening.

Once the master builds its polling list, it send commands to individual slaves as required.

Posted 1-Jul-19 0:34am

Gerry Schmitz

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dj4400 2-Jul-19 10:59am

Thanks Gerry for your answer
In my app. the server sends in broadcast a port number and now the client should send a response through this port

should the client close the broadcast socket and create a new one with the server address and new port or can it use the old socket in some way?

thanks!