How do I add elements of char array after converting it from string to get the numeric value(not ascii value)

Question

0.00/5 (No votes)

See more:

import java.util.*;
public class LuckyNum {
	public static void main(String args[])
	{
		String no="1234";
		char ch[]=no.toCharArray();
		int sum=0;
		for(int i=0;i<4;i++)
			{
			sum=sum+(int)ch[i];}
		System.out.println(sum); 
	}

}

What I have tried:

Here i need to convert string to char array so that i can add each element of string(string is numeric) but the expected output 10 and the actual output is 202.

Posted 27-Jun-19 2:43am

Member 13954890

Updated 27-Jun-19 3:02am

Add a Solution

3 solutions

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

CPallini · Accepted Answer · 2019-06-27T02:59:00

Solution 1

Replace

Quote:
sum=sum+(int)ch[i];

with

sum = sum + (int)(ch[i] - '0');

Posted 27-Jun-19 2:59am

CPallini

Comments

Maciej Los 27-Jun-19 9:37am

You've been faster then me, Carlo
5ed!

CPallini 27-Jun-19 9:43am

Thank you very much, Maciej!

MadMyche 27-Jun-19 9:51am

You've both been +5'd

CPallini 27-Jun-19 10:00am

Thank you!

Maciej Los · Accepted Answer · 2019-06-27T03:00:00

Solution 2

What you're doing in your code is converting char into ascii code and then getting the sum of them. That's why your result is equal 202, not 10.

Check this: How can I convert a char to int in Java? - Stack Overflow[^]

Quote:

Java

char x = '9';
int y = Character.getNumericValue(x);   //use a existing function
System.out.println(y + " " + (y + 1));  // 9  10

or

Java

char x = '9';
int y = x - '0';                        // substract '0' code to get the difference
System.out.println(y + " " + (y + 1));  // 9  10

Posted 27-Jun-19 3:00am

Maciej Los

Updated 27-Jun-19 3:01am

v2

Comments

CPallini 27-Jun-19 9:42am

Have my 5, 'slow man' :-D

Maciej Los 27-Jun-19 12:51pm

Thanks :D

MadMyche 27-Jun-19 9:52am

You've both been +5'd

Maciej Los 27-Jun-19 12:51pm

Thank you very much.

OriginalGriff · Accepted Answer · 2019-06-27T03:02:00

Well ... you could take advantage of the character set order, which has '0' then '1', '2', ... '9' in that order.
So subtracting '0' from each character will give you the value:

Java

import java.util.*;
public class Main {
    public static void main (String args[]) {
        String no = "1234";
        char ch[] = no.toCharArray ();
        int sum = 0;
        for (int i = 0; i < 4; i++) {
            sum = sum + (int) (ch[i] - '0');
            } 
        System.out.println (sum);
        } 
    }

But ... I'd strongly suggest you validate your inputs by checking that they are digits first!