MS SQL view. Two identical fields

Question

1.00/5 (1 vote)

See more:

I'm stuck

there are two fields in the table, of an equal type, joined by "code" field with another table, describing the code

Please suggest

how to create the view to show the description of these two fields from chained table instead of code.

SELECT        dbo.MFU.PrintFormatMaximum, dbo.MFU.PrintFormatMinimum
FROM            dbo.MFU LEFT OUTER JOIN
                         dbo.PrintFormatTypes ON dbo.MFU.PrintFormatMinimum = dbo.PrintFormatTypes.Code AND dbo.MFU.PrintFormatMaximum = dbo.PrintFormatTypes.Code

What I have tried:

forums,
TSQL,
SQL View,
MSDN

Posted 28-Oct-18 22:00pm

po_saa

Updated 28-Oct-18 23:15pm

Add a Solution

Comments

OriginalGriff 29-Oct-18 4:22am

You need to show us sample data for the tables, sample output from your query, and explain what output you are expecting - we can't work it out when you are typing as little as possible!

Remember that we can't see your screen, access your HDD, or read your mind - we only get exactly what you type to work with.
Use the "Improve question" widget to edit your question and provide better information.

[no name] 29-Oct-18 4:46am

I do not realize how to attach the picture and files

OriginalGriff 29-Oct-18 4:48am

Don't: use text. That way, it's easier for us to duplicate your sample data for testing...

[no name] 29-Oct-18 4:56am

sure
the left table "Table_data" is as follows

field1 field2
-------------------
1 2
3 4

the right table "Table_dictionary" is
field_code field_description
----------------------------------
1 one
2 two
3 three
4 four

expected to see in view

field1 field2
----------------------
one two
three four

SELECT dbo.Table_Data.field1, dbo.Table_Data.field2
FROM dbo.Table_Data LEFT OUTER JOIN
dbo.Table_Dictionary ON dbo.Table_Data.field2 = dbo.Table_Dictionary.field_code AND dbo.Table_Data.field1 = dbo.Table_Dictionary.field_code

that is "one chained dictionary table <- many fields"

2 solutions

Solution 2

SQL

--Normal view is invalid after dropping view dependency table.
--we can't drop view dependency table by using "WITH SCHEMABINDING" option in view.
    
CREATE view VName WITH SCHEMABINDING 
 AS 
SELECT  
     MFU.PrintFormatMaximum,
     MFU.PrintFormatMinimum

FROM  dbo.MFU LEFT OUTER JOIN dbo.PrintFormatTypes 
 
  ON dbo.MFU.PrintFormatMinimum = dbo.PrintFormatTypes.Code AND
     dbo.MFU.PrintFormatMaximum = dbo.PrintFormatTypes.Code

Posted 28-Oct-18 22:29pm

Santosh kumar Pithani

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

OriginalGriff · Accepted Answer · 2018-10-28T23:16:00

Quote:
that is "one chained dictionary table <- many fields"

You need two JOINs, one for each column in the original table:

SQL

SELECT d1.field_description AS Field1, d2.field_description AS Field2 FROM Table_data t
JOIN Table_dictionary d1 ON t.field1 = d1.field_code
JOIN Table_dictionary d2 ON t.field2 = d2.field_code