Count the number of iteration in Python

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1.00/5 (1 vote)

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i'am trying to generate a random password using python random library where i've defined a number of alphabets(upper, lower & digit) in a variable and also defined the password length size should be 3(EXAMPLE), now using if statement i tried to check whether the random generated password would match the defined string in if statement. NOW my question is how do i check how much iteration it takes to match the pattern

What I have tried:

Python

import random
sbc = 'abc'
passlen = 3
passwd = ''.join(random.sample(sbc,passlen))
while 1:
    #NOW HOW DO I COUNT HOW MUCH ITERATION DOES IT TAKES TO MATCH THE STRING
    if passwd == 'abc':
        print 'password matched'
        break
print 'bye'

Posted 17-Sep-18 0:55am

Member 13987161

Updated 19-Jan-21 15:21pm

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Richard MacCutchan · Accepted Answer · 2018-09-17T01:07:00

Solution 1

Python

counter = 0
while 1:
    passwd = ''.join(random.sample(sbc,passlen))
    if passwd == 'abc':
        print('password matched')
        break
    print(passwd, "does not match")
    counter += 1

print(counter, "iterations")

Posted 17-Sep-18 1:07am

Richard MacCutchan

Updated 17-Sep-18 1:12am

v2

Comments

CPallini 20-Jan-21 2:11am

5.

Richard MacCutchan 20-Jan-21 4:10am

Thanks Carlo. But why now? :)

CPallini 20-Jan-21 4:16am

I'm a bit ~~retard~~ late...