Inner join result is different

Question

1.00/5 (1 vote)

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Hi,

the below result count is 8 records.

declare @t table (id int)
declare @t2 table(id2 int)
insert into @t values(1),(1),(1)
insert into @t2 values(1),(1),(1)
select t1.id from @t t1 inner join @t2 t2 on t1.id=t2.id2

I think the count should be 9 records

Please suggest.

Thanks

What I have tried:

Inner Join Result is different

Posted 25-Jul-18 18:30pm

Member 13867163

Updated 25-Jul-18 21:21pm

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Comments

CHill60 26-Jul-18 4:11am

When I run your code I get 9 rows

Richard Deeming 26-Jul-18 12:17pm

REPOST
You have already posted this in the database forum:
https://www.codeproject.com/Messages/5540480/inner-join-results.aspx[^]

3 solutions

Solution 2

can you share the query with me so i can check.but in inner join the query will preform as cross join because every row id is same as next row id so that the inner join will join every record in our table column id.

Posted 25-Jul-18 21:08pm

Member 11621026

Comments

Member 13867163 26-Jul-18 3:11am

Exactly. So my doubt is in First Table I have 3 Ids and in second table I have 3 Ids.
So 3X3=9 records should come. But while executing the query I am getting 8 records.

CHill60 26-Jul-18 4:10am

Don't post comments or questions as solutions! Either use the "Have a Question or Comment?" link next to a post or use the "Reply" link next to a comment

Solution 3

that is not possible
only one case can possible for that when one is not match

Posted 25-Jul-18 21:22pm

Member 11621026

Comments

Member 13867163 26-Jul-18 4:23am

No what I mean to say is I have 3 ids are there in table1 I am joining with table 2
row by row base 3 ids in table1 is joined to table2 as below.

First id 1 having matches found 3 ids in table2 so the records are 3 rows.
second id 1 having match found 3 ids in table2 so the records are 3 rows
third id 1 having match found 3 ids in table2 so the records are 3 rows

So totol is 9 records.
But why it is giving 8 records.

Please suggest

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Member 11621026 · Accepted Answer · 2018-07-25T20:44:00

Solution 1

declare @t table (id int)
declare @t2 table(id2 int)
insert into @t values(1),(1),(1)
insert into @t2 values(1),(1),(1)

select a.* from(
select row_number() over(order by id) as Sno,* from @t) as a
inner join(
select row_number() over(order by id2) as Sno,* from @t2) as b
on a.sno=b.sno

Posted 25-Jul-18 20:44pm

Member 11621026

Comments

Member 13867163 26-Jul-18 2:54am

Hi,

Thank you for your reply.
My doubt here is the inner join result is giving 8 records as per my query.
my doubt is as per row by row joining it should be 9 records i think. why 8 records are given. any logic internally.

Please suggest