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class test{
public static void main(String args[]){
b ref=new b();
ref.x=99;
ref.show();
}}
class a{
int x=10;}
class b extends a{
void show(){
a ref=new a();
System.out.println(super.x);}}


What I have tried:

when i compile i am getting answer as 99 but i am not understanding ?
Posted
Updated 5-Apr-18 22:27pm
Comments
Vijay Krishnegowda 6-Apr-18 2:36am    
please explain me how it works

Class b inherits x data member from class a. Your code assigns it and then prints its value. No surprise the output is 99, I have to say.
Please note, in the below code
Quote:
void show(){
a ref=new a();
System.out.println(super.x);}

the statement
Java
a ref=new a();
has NO effect: you are creating a new object and then happily ignoring it.
 
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Quote:
when i compile i am getting answer as 99 but i am not understanding ?

Your code do not behave the way you expect, and you don't understand why !
Use the debugger and see by yourself:

There is an almost universal solution: Run your code on debugger step by step, inspect variables.
The debugger is here to show you what your code is doing and your task is to compare with what it should do.
There is no magic in the debugger, it don't know what your is supposed to do, it don't find bugs, it just help you to by showing you what is going on. When the code don't do what is expected, you are close to a bug.
To see what your code is doing: Just set a breakpoint and see your code performing, the debugger allow you to execute lines 1 by 1 and to inspect variables as it execute.
Debugger - Wikipedia, the free encyclopedia[^]
http://docs.oracle.com/javase/7/docs/technotes/tools/windows/jdb.html[^]
https://www.jetbrains.com/idea/help/debugging-your-first-java-application.html[^]
The debugger is here to only show you what your code is doing and your task is to compare with what it should do.
 
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