How do I get the top 4 salary data in mysql query?

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I have a SQL query table where I need to return:

Salary_amount_1
Salary_amount_2
Salary_amount_3
Salary_amount_4

(not relevant below)
Salary_Date_1
Salary_Date_2
Salary_Date_3
Salary_Date_4

I've got 4 seperate columns for each salary amount to select into, but how do I specifically select the first salary for column 1, second for column two, third for three and fourth salary for column four?
Thanks in advance

What I have tried:

This is what I have (and isn't working for me yet)

min(details_Credit) as Salary_Amount_1,
max(details_Credit) as Salary_Amount_2,
Case
when details_Credit = min(details_Credit)
and details_Credit > min(details_Credit)
end Salary_Amount_3,
NULL as Salary_Amount_4,

Posted 27-Mar-18 0:03am

Member 13748924

Updated 27-Mar-18 14:04pm

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#realJSOP · Answer 1 · 2018-03-27T01:22:00

That's the weirdest sql query I think I've ever seen, but I think this is what you want, based on what you provided.

SQL

select min(details_Credit) as Salary_Amount_1,
       max(details_Credit) as Salary_Amount_2,
       details_Credit as Salary_Amount_3,
       NULL as Salary_Amount_4,

S Douglas · Answer 2 · 2018-03-27T14:05:00

What specifies the salary amount? Based on what you have tried, there is some criteria to what defines the various types of salary base points.

If I had to guess, you are getting some syntax errors?

Have you tried

SELECT
	MIN(details_Credit) as Salary_Amount_1,
	MAX(details_Credit) as Salary_Amount_2,
	CASE 
		WHEN details_Credit < MIN(details_Credit) and details_Credit > MIN(details_Credit) THEN 
			details_Credit
		ELSE
			NULL
		END Salary_Amount_3,
	NULL as Salary_Amount_4,
FROM table;

How do I get the top 4 salary data in mysql query?

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