Automatic build of a treeview

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Hello,
I am trying to automatically build a tree view by giving it the following values.
number of levels :Nlevels
number of children in each level: NchildrenAtEachLevel

Is this doable?

Any help would be highly appreciated.

Posted 28-Oct-10 20:55pm

SuperAdministrator

Updated 28-Oct-10 22:28pm

Dalek Dave

v2

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Arindam Tewary 29-Oct-10 2:59am

This is achiveable/doable. :)

SuperAdministrator 29-Oct-10 3:01am

can you provide me with any help regarding an algorithm ?

Dalek Dave 29-Oct-10 4:28am

Edited for Grammar and Readability.

2 solutions

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Pawan Kiran · Answer 1 · 2010-10-28T21:20:00

Solution 1

Equal No of Childs For Each Parent Node

Private Void FillTreeView(Treeview Tv,int NoofParents,int NoofChilds)
{
  for(int i=0;i< NoofParents;i++)
  {
    Tv.Nodes.Add(i);
    for(int j=0;i< NoofChilds;j++)
    {
       Tv.Nodes[i].Nodes.Add(j);
    }
  }
}

Posted 28-Oct-10 21:20pm

Pawan Kiran

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SuperAdministrator 29-Oct-10 3:25am

This builds a tree with two levels ex: 2 parents with 3 children each . But i need to pass the number of levels so it has to be a kind of recursive method.

qontary · Answer 2 · 2010-10-28T23:05:00

Try this. I modify the code posted by Mr. Pawan Kiran.

C#

private void FillTreeView(TreeView Tv, int NoOfLevels, int NoOfChildsOfEachLevel)
        {
            if (NoOfLevels < 0)
                return;
            for (int i = 0; i < NoOfChildsOfEachLevel; i++)
            {
                Tv.Nodes.Add(i.ToString());
                FillTreeNode(Tv.Nodes[i], NoOfLevels - 1, NoOfChildsOfEachLevel);
            }
        }

        private void FillTreeNode(TreeNode Tn, int NoOfLevels, int NoOfChildsOfEachLevel)
        {
            if (NoOfLevels < 0)
                return;
            for (int i = 0; i < NoOfChildsOfEachLevel; i++)
            {
                Tn.Nodes.Add(i.ToString());
                FillTreeNode(Tn.Nodes[i], NoOfLevels - 1, NoOfChildsOfEachLevel);
            }
        }