How to print the number located in Y'th position of X'th line in an arraylist ?

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Java

Java8

Problem Statement:

Quote:

You are given n lines. In each line there are zero or more integers. You need to answer a few queries where you need to tell the number located in Yth position of Xth line.

Input Format

The first line has an integer n. In each of the next n lines there will be an integer d denoting number of integers on that line and then there will be d space-separated integers. In the next line there will be an integer q denoting number of queries. Each query will consist of two integers x and y.

Output Format

In each line, output the number located in Y'th position of X'th line. If there is no such position, just print "ERROR!"

Quote:

Sample Input

5
5 41 77 74 22 44
1 12
4 37 34 36 52
0
3 20 22 33
5
1 3
3 4
3 1
4 3
5 5

Sample Output

74
52
37
ERROR!
ERROR!

I have written my code till adding elements to the ARRAYLIST. I have tried to print elements in the array list.
My code:

import java.util.*;
public class Solution {

	  public static void main(String[] args) {
	        Scanner scan = new Scanner(System.in);
	        int n = scan.nextInt();
	        ArrayList<Integer> al = new ArrayList<Integer>();
	        for(int i=0;i<n;i++){
	        	int a = scan.nextInt();
	        	al.add(a);
	        	for(int j=0;j<a;j++){
	        	int b = scan.nextInt();
	        		al.add(j,b);
	        	}
	        }
	        scan.close();
	        Iterator<Integer> itr = al.iterator();
	        while(itr.hasNext()){
	            System.out.print(itr.next()+" ");
	        }
	  }
	  }

What I have tried:

My code's Result:
Input:
5
5 41 77 74 22 44
1 12
4 37 34 36 52
0
3 20 22 33
Output:
20 22 33 37 34 36 52 12 41 77 74 22 44 5 1 4 0 3

Now that my output is a sequence of integers which I added to the list, I need some insights on how to print the number located in Y'th position of X'th line.