c++ Structures export data for specific name

Question

2.00/5 (1 vote)

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That is the structure that I created:

C++

#include <iostream>
#include <string>
#include <fstream>
using namespace std;


struct Students
{
	char first_name[10];
	char last_name[10];
	char country[20];


};
int main()
{
	Students array[10];
	int n, i;
	cin >> n;

	for (i = 0; i < n; i++)
	{
		cout << "Name:";
		cin >> array[i].first_name;
		cout << "Last Name:";
		cin >> array[i].last_name;
		cout << "Country:";
		cin >> array[i].country;

	}

	for (i = 0; i < n; i++)
	{
		cout << array[i].first_name << " ";
		cout << array[i].last_name << " ";
		cout << array[i].country << " ";


	}
	system("pause");


}

And I have to write code that once I enter John (for example) displays all information about him: last name, country. And when I enter country to export: first name, last name. Maybe I don't explain it properly. Because my english is bad. Maybe that's the reason that i can't find specific information or similar examples.

Ouput example:

n=2
Name:John
Last Name: Doe
Country: England

Name:Pete
Last Name: Donaldson
Country: USA

And that's the part that i can't do:

/Info about student/
Enter Name for check:
John

and here the output must be:

Name:John
Last Name: Doe
Country: England

another check:
if I enter Pete:

Name:Pete
Last Name: Donaldson
Country: USA

I should be able to make unlimited checks.

I tryed to make it like this:

C++

for (i = 0; i < n; i++)
char name_for_check[10];
cin >> name_for_check;
for (i = 0; i < n; i++)
{
	if (strcmp(array[i].first_name, name_for_check) == 0)
	{
		cout << array[i].first_name << " ";
		cout << array[i].last_name << " ";
		cout << array[i].country << " ";
	}
}
}

But how to do so that I can make an unlimited number of requests for name_for_check.
I mean that i can check name more than one time.

Posted 2-Jan-16 6:00am

Member 12204396

Updated 2-Jan-16 10:06am

v7

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Comments

Sergey Alexandrovich Kryukov 2-Jan-16 14:41pm

It's not clear where your problem is. What have you tried so far?
—SA

Member 12204396 2-Jan-16 14:49pm

I tryed to make it like that but it doesnt work:

for (i = 0; i < n; i++)
{
char name_for_check;
cin >> name_for_check;
if (strcmp(array[i].first_name, name_for_check) == 0)
{
cout << array[i].first_name << " ";
cout << array[i].last_name << " ";
cout << array[i].country << " ";
}
}

Sergey Alexandrovich Kryukov 2-Jan-16 15:19pm

You are trying to input name_for_check n times.
—SA

Member 12204396 2-Jan-16 15:23pm

Yes, actually I'm not really aware of what I do.

Sergey Alexandrovich Kryukov 2-Jan-16 16:55pm

You need to understand each line of what you do.
—SA

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Arthur V. Ratz · Accepted Answer · 2016-01-02T20:05:00

Probably this one, I don't actually understand the condition of the problem being described:

C++

do
{
     char name_for_check[10] = "\0";
     cin >> name_for_check;
     if (strcmp("quit", name_for_check) < 0)
     {
         bool found = false;
         for (i = 0; i < n && found == false; i++)
    	      if (!strcmp(array[i].first_name, name_for_check))
              { 	
		  cout << array[i].first_name << " ";
		  cout << array[i].last_name << " ";
		  cout << array[i].country << " ";
                  found = true;
  	      }
     }
}while(!strcmp("quit", name_for_check));

The following code requsts for a user input infinitely until the string containing "quit" is typed in. I think that it should solve the following problem