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Calculating simple running totals in SQL Server

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12 Dec 2014CPOL4 min read 403.1K   1K   50   36
Some simple scenarios to calculate running totals in SQL Server.

Introduction

One typical question is, how to calculate running totals in SQL Server. There are several ways of doing it and this article tries to explain a few of them.

Test environment

First we need a table for the data. To keep things simple, let's create a table with just an auto incremented id and a value field.

SQL
--------------------------------------------------------------------
-- table for test 
--------------------------------------------------------------------
CREATE TABLE RunTotalTestData (
   id    int not null identity(1,1) primary key,
   value int not null
);

And populate it with some data:

SQL
--------------------------------------------------------------------
-- test data
--------------------------------------------------------------------
INSERT INTO RunTotalTestData (value) VALUES (1);
INSERT INTO RunTotalTestData (value) VALUES (2);
INSERT INTO RunTotalTestData (value) VALUES (4);
INSERT INTO RunTotalTestData (value) VALUES (7);
INSERT INTO RunTotalTestData (value) VALUES (9);
INSERT INTO RunTotalTestData (value) VALUES (12);
INSERT INTO RunTotalTestData (value) VALUES (13);
INSERT INTO RunTotalTestData (value) VALUES (16);
INSERT INTO RunTotalTestData (value) VALUES (22);
INSERT INTO RunTotalTestData (value) VALUES (42);
INSERT INTO RunTotalTestData (value) VALUES (57);
INSERT INTO RunTotalTestData (value) VALUES (58);
INSERT INTO RunTotalTestData (value) VALUES (59);
INSERT INTO RunTotalTestData (value) VALUES (60);

The scenario is to fetch a running total when the data is ordered ascending by the id field.

Correlated scalar query

One very traditional way is to use a correlated scalar query to fetch the running total so far. The query could look like:

SQL
--------------------------------------------------------------------
-- correlated scalar
--------------------------------------------------------------------
SELECT a.id, a.value, (SELECT SUM(b.value)
                       FROM RunTotalTestData b
                       WHERE b.id <= a.id)
FROM   RunTotalTestData a
ORDER BY a.id;

When this is run, the results are:

id   value   running total
--   -----   -------------
1    1       1
2    2       3
3    4       7
4    7       14
5    9       23
6    12      35
7    13      48
8    16      64
9    22      86
10   42      128
11   57      185
12   58      243
13   59      302
14   60      362

So there it was. Along with the actual row values, we have a running total. The scalar query simply fetches the sum of the value field from the rows where the ID is equal or less than the value of the current row. Let us look at the execution plan:

RunningTotalWithSQLServer/600_CorrelatedScalarPlan.jpg

What happens is that the database fetches all the rows from the table and using a nested loop, it again fetches the rows from which the sum is calculated. This can also be seen in the statistics:

Table 'RunTotalTestData'. Scan count 15, logical reads 30, physical reads 0...

Using join

Another variation is to use join. Now the query could look like:

SQL
--------------------------------------------------------------------
-- using join 
--------------------------------------------------------------------
SELECT a.id, a.value, SUM(b.Value)
FROM   RunTotalTestData a,
       RunTotalTestData b
WHERE b.id <= a.id
GROUP BY a.id, a.value
ORDER BY a.id;

The results are the same but the technique is a bit different. Instead of fetching the sum for each row, the sum is created by using a GROUP BY clause. The rows are cross joined restricting the join only to equal or smaller ID values in B. The plan:

RunningTotalWithSQLServer/600_SubsetJoinPlan.jpg

The plan looks somewhat different and what actually happens is that the table is read only twice. This can be seen more clearly with the statistics.

Table 'RunTotalTestData'. Scan count 2, logical reads 31...

The correlated scalar query has a calculated cost of 0.0087873 while the cost for the join version is 0.0087618. The difference isn't much but then again it has to be remembered that we're playing with extremely small amounts of data.

Using conditions

In real-life scenarios, restricting conditions are often used, so how are conditions applied to these queries. The basic rule is that the condition must be defined twice in both of these variations. Once for the rows to fetch and the second time for the rows from which the sum is calculated.

If we want to calculate the running total for odd value numbers, the correlated scalar version could look like the following:

SQL
--------------------------------------------------------------------
-- correlated scalar, subset
--------------------------------------------------------------------
SELECT a.id, a.value, (SELECT SUM(b.value)
                       FROM RunTotalTestData b
                       WHERE b.id <= a.id
                       AND b.value % 2 = 1)
FROM  RunTotalTestData a
WHERE a.value % 2 = 1
ORDER BY a.id;

The results are:

id   value   runningtotal
--   -----   ------------
1    1       1
4    7       8
5    9       17
7    13      30
11   57      87
13   59      146

And with the join version, it could be like:

SQL
--------------------------------------------------------------------
-- with join, subset
--------------------------------------------------------------------
SELECT a.id, a.value, SUM(b.Value)
FROM   RunTotalTestData a,
       RunTotalTestData b
WHERE b.id        <= a.id
AND   a.value % 2  = 1
AND   b.value % 2  = 1
GROUP BY a.id, a.value
ORDER BY a.id;

When actually having more conditions, it can be quite painful to maintain the conditions correctly. Especially if they are built dynamically.

Calculating running totals for partitions of data

If the running total needs to be calculated to different partitions of data, one way to do it is just to use more conditions in the joins. For example, if the running totals would be calculated for both odd and even numbers, the correlated scalar query could look like:

SQL
--------------------------------------------------------------------
-- correlated scalar, partitioning
--------------------------------------------------------------------
SELECT a.value%2, a.id, a.value, (SELECT SUM(b.value) 
                               FROM RunTotalTestData b
                               WHERE b.id <= a.id
                               AND b.value%2 = a.value%2)
FROM   RunTotalTestData a
ORDER BY a.value%2, a.id;

The results:

even   id   value   running total
----   --   -----   -------------
0      2    2       2
0      3    4       6
0      6    12      18
0      8    16      34
0      9    22      56
0      10   42      98
0      12   58      156
0      14   60      216
1      1    1       1
1      4    7       8
1      5    9       17
1      7    13      30
1      11   57      87
1      13   59      146

So now the partitioning condition is added to the WHERE clause of the scalar query. When using the join version, it could be similar to:

SQL
--------------------------------------------------------------------
-- with join, partitioning
--------------------------------------------------------------------
SELECT a.value%2, a.id, a.value, SUM(b.Value)
FROM   RunTotalTestData a,
       RunTotalTestData b
WHERE b.id      <= a.id
AND   b.value%2  = a.value%2
GROUP BY a.value%2, a.id, a.value
ORDER BY a.value%2, a.id;

With SQL Server 2012

SQL Server 2012 makes life much more simpler. With this version, it's possible to define an ORDER BY clause in the OVER clause.

So to get the running total for all rows, the query would look:

SQL
--------------------------------------------------------------------
-- Using OVER clause
--------------------------------------------------------------------
SELECT a.id, a.value, SUM(a.value) OVER (ORDER BY a.id)
FROM   RunTotalTestData a
ORDER BY a.id;

The syntax allows to define the ordering of the partition (which in this example includes all rows) and the summary is calculated in that order.

To define a condition for the data, it doesn't have to be repeated anymore. The running total for odd numbers would look like:

SQL
--------------------------------------------------------------------
-- Using OVER clause, subset
--------------------------------------------------------------------
SELECT a.id, a.value, SUM(a.value) OVER (ORDER BY a.id)
FROM   RunTotalTestData a
WHERE a.value % 2 = 1
ORDER BY a.id;

And finally, partitioning would be:

SQL
--------------------------------------------------------------------
-- Using OVER clause, partition
--------------------------------------------------------------------
SELECT a.value%2, a.id, a.value, SUM(a.value) OVER (PARTITION BY a.value%2 ORDER BY a.id)
FROM   RunTotalTestData a
ORDER BY a.value%2, a.id;

What about the plan? It's looking very different. For example, the simple running total for all rows looks like:

RunningTotalWithSQLServer/600_OverOrderBy.jpg

And the statistics:

Table 'Worktable'. Scan count 15, logical reads 85, physical reads 0...
Table 'RunTotalTestData'. Scan count 1, logical reads 2, physical reads 0...

Even though the scan count looks quite high at first glance, it isn't targeting the actual table but a worktable. The worktable is used to store intermediate results which are then read in order to create the calculated results.

The calculated cost for this query is now 0.0033428 while previously with the join version, it was 0.0087618. Quite an improvement.

References

History

  • December 16, 2011: Created.
  • December 13, 2014: Invalid reference links updated

License

This article, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)


Written By
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Europe Europe
Biography provided

Comments and Discussions

 
QuestionCalculating simple running totals in SQL Server Pin
PmJN23-Sep-19 5:31
PmJN23-Sep-19 5:31 
AnswerRe: Calculating simple running totals in SQL Server Pin
Wendelius23-Sep-19 16:44
mentorWendelius23-Sep-19 16:44 
Thanks for the question,

I'm not sure if I fully understand the situation. Could you give more details what you're after, some examples perhaps?

Cheers,

GeneralRe: Calculating simple running totals in SQL Server Pin
PmJN24-Sep-19 0:39
PmJN24-Sep-19 0:39 
QuestionRemove item from running total and recalculate Pin
Member 1115704222-Jul-15 9:42
Member 1115704222-Jul-15 9:42 
AnswerRe: Remove item from running total and recalculate Pin
Wendelius22-Jul-15 9:50
mentorWendelius22-Jul-15 9:50 
GeneralReally nice. Pin
db7uk18-Dec-14 22:58
db7uk18-Dec-14 22:58 
GeneralRe: Really nice. Pin
Wendelius19-Dec-14 1:12
mentorWendelius19-Dec-14 1:12 
QuestionThanks Pin
Sanket S Sonavane17-Sep-14 20:27
Sanket S Sonavane17-Sep-14 20:27 
AnswerRe: Thanks Pin
Wendelius17-Sep-14 21:41
mentorWendelius17-Sep-14 21:41 
GeneralMy vote of 5 Pin
dotNetEP27-Jun-14 5:46
dotNetEP27-Jun-14 5:46 
GeneralRe: My vote of 5 Pin
Wendelius1-Sep-14 6:28
mentorWendelius1-Sep-14 6:28 
Questionvery helpful Pin
Yuriy Loginov28-May-14 3:41
professionalYuriy Loginov28-May-14 3:41 
AnswerRe: very helpful Pin
Wendelius1-Sep-14 6:28
mentorWendelius1-Sep-14 6:28 
Questionhow to use over clause with a join? Pin
ivanlewis25-Dec-13 22:46
ivanlewis25-Dec-13 22:46 
AnswerRe: how to use over clause with a join? Pin
Wendelius26-Dec-13 21:02
mentorWendelius26-Dec-13 21:02 
GeneralRe: how to use over clause with a join? Pin
ivanlewis5-Jan-14 1:30
ivanlewis5-Jan-14 1:30 
GeneralMy vote of 5 Pin
hadeed147229-Dec-12 0:05
hadeed147229-Dec-12 0:05 
GeneralRe: My vote of 5 Pin
Wendelius29-Dec-12 0:07
mentorWendelius29-Dec-12 0:07 
QuestionExcellent. but side question Pin
fronjm0513-Nov-12 14:41
fronjm0513-Nov-12 14:41 
AnswerRe: Excellent. but side question Pin
Wendelius29-Dec-12 0:10
mentorWendelius29-Dec-12 0:10 
QuestionSome Suggessions Pin
Asif Rehman30-Oct-12 5:02
Asif Rehman30-Oct-12 5:02 
AnswerRe: Some Suggessions Pin
Wendelius30-Oct-12 6:37
mentorWendelius30-Oct-12 6:37 
GeneralMy vote of 5 Pin
Luc Pattyn9-Feb-12 1:25
sitebuilderLuc Pattyn9-Feb-12 1:25 
GeneralRe: My vote of 5 Pin
Wendelius9-Feb-12 7:22
mentorWendelius9-Feb-12 7:22 
GeneralRe: My vote of 5 Pin
Luc Pattyn9-Feb-12 8:02
sitebuilderLuc Pattyn9-Feb-12 8:02 

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