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Does passing a tracking reference work?
void CLIClass::InitArray(array<float>^% a)
Mark Salsbery
![Java | [Coffee]](https://codeproject.global.ssl.fastly.net/script/Forums/Images/coffee.gif)
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Yes, all I was missing is the % operator. Thanks!
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I gave him a 5. It's nice when you do that when people help you out here.
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your C# code should use the out or ref keyword:
float[] a;
InitArray(out a);
float[] a=null;
InitArray(ref a);
ref would fail here as long as a isn't initialized.
Without ref/out your callee can modify the array content, however it can't replace the array.
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******************************************************
the code works as follows.
If you chose them all, works fine, but not all, of one or more than one election, or choose not at all, the program does not work
stands in this code.
if (dr.Cells [0]. Value.ToString ()! = "true")
How do we solve the problem?
List<int> TestId = new List<int>();
for (int i = 0; i < dataGridView2.RowCount; i++)
{
foreach (DataGridViewRow dr in dataGridView2.Rows)
{
if (dr.Cells[0].Value.ToString() != "true")
{
TestId.Add(Convert.ToInt32(dr.Cells[2].Value.ToString()));
}
}
}
if (baglanti.State == ConnectionState.Closed)
baglanti.Open();
komut.Connection = baglanti;
for (int i = 0; i < TestId.Count; i++)
{
komut.CommandText = "update HASTA_SONUCLARI SET ONAYLANDI='" + true + "' where PROTOKOL_NO='" + TextBox6.Text + "' and TEST_NO='" + TestId + "'";
komut.ExecuteNonQuery();
}
MessageBox.Show("Onaylandı.");
baglanti.Close();
}
}
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what a horrible message. The code isn't formatted properly, there are plenty of unjustified ToString() calls and string comparisons, and "doesn't work" doesn't even start to explain what the problem is.
Please read the forum guidelines ("How to get an answer to your question" at the top of this forum), and see how others post their message. Good questions yield good answers here.
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Actually I wanted to report this message to the Hall of Shame.
Look:
- You run in nested loops several times through your DataGridView
for (int i = 0; i < dataGridView2.RowCount; i++) {
foreach (DataGridViewRow dr in dataGridView2.Rows)
- You compare boolean values as a strings - it will fail with localized versions!
if (dr.Cells[0].Value.ToString() != "true")
By the way, I posted such a coding horror some time ago. It was very hard to find out why the program strangely failed on that one computer.
- You create SQL queries by adding strings together. TextBox6 might contain bad code (SQL injection attack). Use parameterized queries instead.
- You add an array of numbers where one number is required:
and TEST_NO='" + TestId + "'";
instead of
and TEST_NO='" + TestId[i] + "'";
And that looks like using strings instead of numbers...
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Hi,
i want do send an email, with a 'link' including parameters to a pc user. If the user clicks on this link a specific webforms c# application should be started, if it is not running, and than an action should be executed.
Example MailText:
New image received: 'myapplication<imageid=2000>'
Clicking on 'myapplication<imageid=2000>' should (start the application if it is not running and) load my image with id 2000 from db and show it in my application for example.
Is there a easy way to get it work?
The application is not installed locally, it is only available as webforms application.
I did not know how i must define and setup the link in the email in that way, that the user click on the link (with parameters) in the mail is delegated to and handled by my application.
Did someone maybe know a manual or demo project for this case?
Greetings Frank
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Using the Process class[^], you can start a new application in a program of your choice.
Here[^] is a neat sample of how this class has been used to start Notepad.
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It sounds like you want a url link to your web app with a parameter. This can be done simply by including the URL string in the body of the mail. Surely that can't be the issue.
On the other hand if you are wanting to install your application on the recipients hard disk you are talking about the same delivery method as malware, not a good idea.
Never underestimate the power of human stupidity
RAH
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Hello
I am trying to add a service reference to my solution but it propmpts me errors I use the Ip address with web browsers and it works but when i add the service to my solution it gives me this error
the IP address is MYIP:88/sapco/sapcoservice.asmx?wsdl'
Metadata contains a reference that cannot be resolved: 'http://MYIP:88/sapco/sapcoservice.asmx?wsdl'.
There was an error downloading 'http://MYIP:88/sapco/sapcoservice.asmx?wsdl'.
The request failed with HTTP status 404: Not Found.
Metadata contains a reference that cannot be resolved: 'http://MYIP:88/sapco/sapcoservice.asmx'.
Metadata contains a reference that cannot be resolved: 'http://MYIP/sapco/sapcoservice.asmx'.
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You have already posted this in the WCF and Visual Basic forums; please selct one forum only for your questions.
Unrequited desire is character building. OriginalGriff
I'm sitting here giving you a standing ovation - Len Goodman
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Can anyone tell me why I cannot get this code to write to my serial port (microchip) ?
If I send "pin1=2" via the simpleserial object, it is received and the microchip code reacts. When I try and send it through the below method, the data is not received by the microchip and it does not react.
Thanks for reading.
using System;
using System.Collections.Generic;
using System.Text;
using System.IO.Ports;
using System.Windows.Forms;
namespace SimpleSerial
{
class test
{
private void serialPortWrite()
{
SerialPort serialPort1 = new SerialPort();
string lineToWrite = "pin1=2";
serialPort1.PortName = "COM8";
serialPort1.BaudRate = 115200;
serialPort1.DataBits = 8;
serialPort1.Parity = Parity.None;
serialPort1.StopBits = StopBits.One;
serialPort1.Open();
MessageBox.Show(lineToWrite);
foreach (char chr in lineToWrite)
{
char[] buff = new char[1];
buff[0] = chr;
serialPort1.Write(buff, 0, 1);
}
serialPort1.Close();
}
}
}
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Looks like it must be in the options you're using; the write code is the same. (Though I don't understand why you send one byte at a time.)
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Hi Bob,
Thanks for the reply. As you can see, I tried the "writeline" method as well.
In the simpleserial code example, they wrote one byte at a time as a keypress event and so I was trying to mimic that when troubleshooting after "writeline" didn't work.
What do you mean by "options"?
private void textBox1_KeyPress(object sender, KeyPressEventArgs e)
{
if (!serialPort1.IsOpen) return;
char[] buff = new char[1];
buff[0] = e.KeyChar;
serialPort1.Write(buff, 0, 1);
e.Handled = true;
}
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In .NET strings and char contain 16-bit Unicode characters. So your serialPort1.Write(buff, 0, 1) is writing one character, i.e. two bytes; for ASCII characters that effectively means there is a NULL character preceeding every character you really want.
And yes, the MSDN documentation states that ASCII encoding is the default for SerialPort, but something isn't quite right about that. Either set the Encoding property explicitly, or (what I normally do) construct a byte array yourself and send that using the other Write overload.
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Hi Luc!
Thanks for the reply. I set the encoding explicitly and it is not working yet. Can you expand on what you mean by saying that each character that is written is 2 bytes? This is confusing since it should only take 1 byte for each character.
As for the construction of a byte array, should that be something like (even though the compiler doesn't like the equals sign in this case below)
byte[] bytArr = new byte[] { p, i, n, 2, =, 2 };
And then say serialPort1.WriteLine(bytArr)?
or
foreach (byte byt in bytArr)
{
serialPort1.WriteLine(byt)
}
Is that what you are meaning?
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There are many mistakes in your message now, you really should brush up on C# IMO.
The other overload of Write() obviously is called Write() too, it differs by its parameter list (it takes a byte array instead of a char array).
There are basically two ways of operating a serial port:
- either you claim it all is text and let the system handle the details;
- or you take charge of each and every byte, i.e. you let the system treat it as bytes-not-to-be-touched.
WriteLine() is a text-oriented method, it deals with characters (which are 16-bit normally) AND appends a NewLine (which on Windows by default contains CR LF). That is NOT what you want.
I've had some trouble with SerialPort and ASCII (or any other single-byte) text. In my experience the default Encoding is Unicode, and NOT ASCII, no matter what the doc says; Unicode would send the low and high bytes of the 16-bit character value. Sometimes setting once Encoding=Encoding.ASCII explicitly before sending/receiving anything seems to suffice, however I generally prefer to take full control, hence use byte arrays.
In byte[] bytArr = new byte[] { p, i, n, 2, =, 2 }; the assignment is OK, it is the initialization that is faulty; you can't type letters like that, they need single quotes; and then the compiler would tell you a character doesn't fit in a byte.
One way would be:
byte[] bytes=new byte[6];
bytes[0]=(byte)'p';
...
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Hi Luc,
You'll have to forgive my ignorance, serial data and byte arrays are something I have not ever done until now.
The byte array with the overload is not working, so it looks like I will just have to figure it out through attrition. For some reason the simpleserial object works, but I can't mimic that in my own test program, the only difference that I can see is that the keypress event is occurring and capturing each character and sending it that way. I don't know how this event changes things, but it appears that it does. When I port this over to the simpleserial object for testing, and use the byte array or char array, the simpleserial object breaks, when it put it back to the code below with writing a single char from a char array, it works fine.
private void textBox1_KeyPress(object sender, KeyPressEventArgs e)
{
if (!serialPort1.IsOpen) return;
char[] buff = new char[1];
buff[0] = e.KeyChar;
serialPort1.Write(buff, 0, 1);
}
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You're still sending text, and so you are probably back now at sending two bytes, the one you intend and a NULL, as e.g. 'A' in ASCII is 0x41 but in Unicode it is 0x0041.
try this:
byte[] buff=new byte[1];
buff[0]=(byte)e.KeyChar;
serialPort1.Write(buff, 0, 1);
Once that works, fill an entire byte array as I told you before. That should work too, except there is a tiny chance your target isn't coping with a byte array at top speed, I noticed you are using a high baud rate, no parity, and a single stop bit, which is about the fastest you can hope for, however it might flood the target; remember for serial port, the source must use at least as many stop bits as the target is expecting, more is fine, less is not.
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Yes your example did work correctly. I understand what you are saying with the preceding null character and sending a word instead of a byte.
The uC is set to 115200, 8N1 and it has been ok at this speed using prebuilt terminals.
I have been trying to fill a byte array as instructed, but it is not working as the previous example. I believe text is still being sent, but I am not sure as to why at this point.
byte[] buff = new byte[1];
buff[0] = (byte)'a';
serialPort1.Write(buff, 0, 1);
No luck with this either
byte[] buff = new byte[3];
buff[0] = (byte)'a';
buff[1] = (byte)'b';
buff[2] = (byte)'c';
serialPort1.Write(buff, 0, buff.Length);
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Those two snippets look OK, they send bytes, not text. There may be text in the bytes, but technically it is binary data as far as the PC can tell. Two suggestions:
1.
doesn't the target expect some "end-of-command" indication, maybe a CR or a LF or both? If so, add it to the byte array in the exact same way you do other ASCII characters.
2.
Timing issues:
2a. you did not understand well I'm afraid; if the target accepts 8N1, the source is allowed to use 8N2 which slows down the communication by 10% but may be enough for the target to keep up.
2b. if you open the port, adjust it settings, and send something all in a row, without any delays, most targets I have encountered will just not hear the message, they are still getting ready to listen (opening the port is likely to set one of the control lines, which in turn interrupts the target, signalling something might be going to happen, etc). Hence, open the port in advance, wait 10 msec (NOT inside a button_click handler!), then communicate.
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Luc,
You're the man. Thanks for sticking with me, I really appreciate it ... the CR was what was missing at the end of the byte array.
When I send that, I'm able to send data and have it recognize it. Thanks again for the lesson! I guess the keypress event sends that behind the scenes? I did not know that the chip looked for that before now.
byte[] buff = new byte[7];
buff[0] = (byte)'p';
buff[1] = (byte)'i';
buff[2] = (byte)'n';
buff[3] = (byte)'2';
buff[4] = (byte)'=';
buff[5] = (byte)'3';
buff[6] = (byte)13;
serialPort1.Write(buff, 0, buff.Length);
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You're welcome. I'm glad you got it working.
turbosupramk3 wrote: I guess the keypress event sends
Not at all. Something else must have been going on.
turbosupramk3 wrote: I did not know that the chip looked for that
That should have been obvious: after receiving some digits, how would it know the number is complete? either there is a strict syntax (that many digits), or a time-out (not a nice idea), or there must be a terminator. Everything being ASCII, a CR terminator would be the obvious choice IMO.
turbosupramk3 wrote: I really appreciate it
Then start upvoting whatever message(s) actually helped you.
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