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I disabled it; that didn't help.
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I create an instance of Word by
app.CreateDispatch("Word.Application");
In task manager I can see this has started winword.exe with these command arguments:
WINWORD /Automation -Embedding
But I want it to start with
WINWORD /a /Automation -Embedding
Is there any way to make CreateDispatch start word with: "WINWORD /a /Automation -Embedding" ?
There is sufficient light for those who desire to see, and there is sufficient darkness for those of a contrary disposition.
Blaise Pascal
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Doubt it - I think those arguments are probably stored in the registry, under the registration information for Word as a local COM server. I guess if you wanted to hack the registry...but that's a bad idea, I think.
Java, Basic, who cares - it's all a bunch of tree-hugging hippy cr*p
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Well, I actually might have considered it (changing the registry before making the call to CreateDispatch and changing it back immediately after), but I think I can't do it as a limited user, because the key is in CLASSES_ROOT. I'm going to check on that. Anyway, thanks.
There is sufficient light for those who desire to see, and there is sufficient darkness for those of a contrary disposition.
Blaise Pascal
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It just so happens that I have a little sample app that automates Excel, so I modified it slightly to a) automate Word as well, and b) call a method on a thread (I use Boost.Threads for this because it makes it so much easier than raw Win32 threads). This app is quite happy to make Excel or Word method calls on a thread other than the one that created the Word/Excel instance - here's the code (missing some #includes, but you get the drift):
#include <boost/thread.hpp>
#import "libid:00020813-0000-0000-C000-000000000046" version("1.6") auto_search no_dual_interfaces rename("DialogBox", "excelDialogBox") rename("RGB", "excelRGB") rename("DocumentProperties", "excelDocumentProperties") rename("SearchPath", "excelSearchPath") rename("CopyFile", "excelCopyFile") rename("ReplaceText", "excelReplaceText")
#import "libid:00020905-0000-0000-C000-000000000046" version("1.6") auto_search no_dual_interfaces rename("RGB", "wordRGB") rename("ReplaceText", "wordReplaceText") rename("FindText", "wordFindText") rename("ExitWindows", "wordExitWindows")
void GetActiveDocName(Word::_ApplicationPtr const& wd, _bstr_t& name)
{
try
{
name = wd->ActiveDocument->Name;
}
catch(_com_error& e)
{
name = L"No name";
}
}
void GetActiveWorkbookName(Excel::_ApplicationPtr const& xl, _bstr_t& bs)
{
if (Excel::_WorkbookPtr wb = xl->ActiveWorkbook)
{
try
{
bs = wb->FullName;
}
catch(_com_error& e)
{
bs = L"No name";
}
}
}
int _tmain(int argc, _TCHAR* argv[])
{
CoInitializeEx(0, COINIT_MULTITHREADED);
{
Excel::_ApplicationPtr xl;
if (SUCCEEDED(xl.CreateInstance(__uuidof(Excel::Application))))
{
xl->Workbooks->Add();
_bstr_t name;
boost::thread getName(GetActiveWorkbookName, boost::cref(xl), boost::ref(name));
getName.join();
std::cout << (char*)name << std::endl;
}
Word::_ApplicationPtr wd;
if (SUCCEEDED(wd.CreateInstance(__uuidof(Word::Application))))
{
wd->Documents->Add();
_bstr_t name;
boost::thread getName(GetActiveDocName, boost::cref(wd), boost::ref(name));
getName.join();
std::cout << (char*)name << std::endl;
}
}
CoUninitialize();
return 0;
}
This code, when run, displays correct names. So - it IS possible to call Word on a thread other than the one that instantiated it...
Java, Basic, who cares - it's all a bunch of tree-hugging hippy cr*p
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Hi,
I have a static pointer in a class and im allocating memory in heap in a static function..and that function returns the same pointer...
then im using that function in some other class...now when should i deallocate the memory in heap....in the destructor of the class where the static pointer belongs to...?
Please correct me if im wrong..
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The first thing which is important to understand here is that the static member of a class is shared across all instances of that class. It means that if you destroy your pointer inside the desctrutor of your class, as soon as one instance gets destroyed, then you end up with an invalid pointers for all other instances.
And also, if you allocate that pointer inside a static function, each time the function is called, the pointer will be recreated (which will lead to memory leak), unless you check if it has already been created.
Is there a valid reason why you need to have this static pointer ? If yes, then you will need to destroy that pointer when you don't have any class instances anymore.
Could you please explain the scenario here ?
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ya ill explain....
i have function which calculates the font ie...
CFont* Temp::m_newFont=NULL;
void Temp::init(CDC*pDc)
{
NONCLIENTMETRICS ncmet;
ncmet.cbSize = sizeof(ncmet);
SystemParametersInfo(SPI_GETNONCLIENTMETRICS, sizeof(ncmet), &ncmet, 0);
m_newFont=new CFont;
LOGFONT lf;
HDC hDC=pDc->GetSafeHdc();
SecureZeroMemory(&lf, sizeof(lf));
lf.lfHeight = -MulDiv(20, GetDeviceCaps(hDC, LOGPIXELSY), 72);
lf.lfWeight = FW_MEDIUM;
lstrcpy(lf.lfFaceName,ncmet.lfMenuFont.lfFaceName);
m_newFont->CreateFontIndirect(&lf);
}
and other function which returns pointer..
CFont* Temp::getFont()
{
return m_newFont;
}
where as the above 2 functions are static functions and m_newFont(member varibale) is a static CFont*...
and now im exporting this class using _declspec(dllexport)
and im using this class in some other process..as below...
where pDc is a CDC pointer..
Temp::init(pDC);
and when im trying to use
LOGFONT lf;
CFont* pFont=Temp::getFont();
pFont->GetLogFont(&lf);
lf.lfHeight value is garbage value.....instead of correct value
and when i used Quickwatch and see pFont i see m_hObject as 0x00000000
im not able to understand why it"s getting null..
and even i tried like instead of creating a static pointer i created static CFont object and in getFont() i returned address of the object ...but even that doesn"t help...
pls let me know..
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Cedric Moonen wrote: The first thing which is important to understand here is that the static member of a class is shared across all instances of that class
I've always thought that this is a bit misleading, it's really just a global variable/function, and the class acts only as a namespace. I've read that explanation about being "shared across all instances of that class" and I think it confuses people rather that give them an accurate idea of what a static member is.
There is sufficient light for those who desire to see, and there is sufficient darkness for those of a contrary disposition.
Blaise Pascal
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Please help to solve these scenario of process waiting for execution in C++
Scenario is as follows
There is one parent process say P1 and 4 child processes say A B C D
Process A starts at 3:00 pm
Process B starts at 3:15 pm
Process C starts at 3:30 pm
Process D starts at 3:45 pm
Process A take 1 hour for completion and process B,C,D takes
10 mins for completion
At a time only one process is allowed to execute since
these process shared some common resources so at any point of time
only one process is allowed to execute. but these are scheduled job so
process B, C, and D must wait till process A get completes
so process B must wait till 4:00 PM for execution
and starts at 4:00 PM
process C must start at 4:10 PM after completion of process A and B
process D must start at 4:20 PM after completion of process A and B and C
so these sequencing also should maintained
B, C and D cannot start unless and until A is get completed and user dose not know how much time A will take so B,C and D must wait for completion of A and after A completes then and then only B,C and D execute in a same order
so how to implement wait mechanism for this scenario ?
Currently i have implemented a lock mechanism where first process A will create a lock file and process B,C and D will continuously poll this lock file and as soon as process A finishes it will release a lock on and whichever process acquires a lock first will get executed first but here sequencing is not maintained and process executes randomly
so what kernel objects like event, semaphore are needed to solve this scenario.
Where to store data (simple command line) when this process are waiting ?
How to maintain a sequence for excutation ?
please help to solve this scenario of process waiting for execution
-Thanks
modified on Thursday, August 13, 2009 9:46 AM
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Given your description... I don't think you need much in the way of kernel stuff.
This is very loose code, as I don;t have my compiler handy,
struct Task
{
sometimestruct Time;
THREAD_ROUTINE Thread;
};
Task tasks [] = { { MakeTimeSomehow (1515), TaskA}, { MakeTimeSomehow (1600), TaskB}, ... { 0, NULL} };
for (nTask; tasks [nTask]; nTask++)
{
int nSeconds = TimeBetweenNowAnd (tasks [nTask].Time);
if (nSeconds < 0) nSecconds = 0;
Sleep (1000 * nSeconds);
HANDLE hThread = StartThread (tasks [nTask].Thread, ......);
WaitForHandle (hThread);
CloseHandle (hThread);
}
Job done!
I might just put in some abort flag too... I only expect this to give you an idea. The main trick is that a thread handle is waitable, just like events, semaphores, etc.
Iain.
I have now moved to Sweden for love (awwww).
If you're in Scandinavia and want an MVP on the payroll (or happy with a remote worker), or need cotract work done, give me a job! http://cv.imcsoft.co.uk/[ ^]
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s v joshi wrote: At a time only one process is allowed to execute since
That implies a mutex - the running process owns the mutex, the others wait (using WaitForSingleObject, for example) for the mutex to become free.
Java, Basic, who cares - it's all a bunch of tree-hugging hippy cr*p
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Hi,
In an older (MSVC++6.0) project I used HideControl(edt1) to hide the filename edit control in a CFileDialog derrived class, which worked fine at the time.
When I compile this project with MSDEV2008, the code complies OK but control is no longer hidden.
Other controls that I have hidden appear to work OK, its just 'edt1' that wont go away!
Heres my code:
BOOL CFolderDialog::OnInitDialog()
{
CFileDialog::OnInitDialog();
GetParent()->;SetWindowText(_T("Select Folder"));
SetControlText(IDOK, _T("OK"));
HideControl(stc2);
HideControl(stc3);
HideControl(cmb1);
HideControl(edt1);
return TRUE;
}
Anyone else come across this? 
TIA
Tony
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Using Spy++ on a sample application I just built, it would seem that instead of edt1, you now want to use cmb13 (0x47c). I guess they decided that as that field is (now) actually a combo-box, that would be a better ID to use.
Java, Basic, who cares - it's all a bunch of tree-hugging hippy cr*p
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Thanks for this - it works a treat.
I wish I had thought of using Spy++!
Tony
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Weeeeell, I don;t actually know the answer, but my first idea would be to use Spy++ and see what the ID numbers of the various controls you want to hide are. Any any child windows of other child windows?
Having done that, search for the numerical values of (stc3m stc2, edt1), and see if they match up with results from Spy++.
If all but edt1 match up, then you know the idea is right - then just use the right ID number.
Good luck,
Iain.
Edit:
Stuart has done the work for you, being a nice chappy. But if you follow my email, you can work it out yourself for learning purposes.
I have now moved to Sweden for love (awwww).
If you're in Scandinavia and want an MVP on the payroll (or happy with a remote worker), or need cotract work done, give me a job! http://cv.imcsoft.co.uk/[ ^]
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Hi,
I don't know if this the right place for my problem, but I hope somebody can help me.
I encountered the strange behavior of my OnUpdate function in Cview. I have my own class derived from CView that onUpdate loads the selected data from document and displays them. I am selecting the data using treeControl so whenever I select an item in the tree I set some data from the document to be selected and call UpdateAllViews (so my view calls OnUpdate function).
The problem is that my view displays the data selected in the previous step (set by previously clicked treeitem) and not the actual. But when I place a breakpoint in the OnUpdate function every thing works fine.
I found on google somebody having the similar problem but without any answer.
Thank you very much for your reply
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Could it be that your views simply don't get redrawn? If you put the breakpoint in your code and hit it that will bring Visual Studio's window to top and then if you let your code run (hit F5) it will bring your application's window on screen again which will trigger a redraw and you see your changes, however, without the breakpoint the redraw does not take place so you don't see any change. Try running your app without the breakpoint, select something in your tree and then try "ALT-TABbing" to VS (so VS will cover your window) and then back to your app to trigger a redraw, if then you see what you are suposed to see and not the previous state then you are probably just missing a redraw after the update. Good luck.
> The problem with computers is that they do what you tell them to do and not what you want them to do. <
> Life: great graphics, but the gameplay sux. <
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You were right,
I feel ashamed I didn't figured it out by myself. I called wrong function for redrawing the view.
Thank you
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Hello, I'm trying to create a virtual desktop manager and I need a way to capture a screen shot of all the desktops.
To do this I use a code that capture the screen shot of the desktop in which it is launched but if the desktop is not the input desktop the image captured is just a black rectangle.
To avoid the problem I made my program switch to the desktop to be captured and back. Obviously the result is not really beautiful (the image is ok, but windows has to switch to a different desktop for a couple of seconds each virtual desktop!!!)
Can enyone tell me how can I take a screen schot of the non-input desktops without switching to them first?
I hope it's not too confusing  and theks in advance for your help 
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Just out of curiosity, did you try using PrintWindow[^] or WM_PRINT[^] by any chanche? Did these also fail?
> The problem with computers is that they do what you tell them to do and not what you want them to do. <
> Life: great graphics, but the gameplay sux. <
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I am looking for some help to create a random name generator with ASCII. I am new to C++ and really and not 100% sure how to attack this. "First and last names should be randomly generated and must begin with a capital letter. Additionally, the first letter should be a consonant. The remainder of the name should alternate between vowels and consonants, where every even numbered letter is a vowel and every odd numbered letter is a consonant." Any help would be GREAT!!.
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Looks like homework. What is your trouble about?
Hint: create two arrays (for consonants and vowels).
If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.
This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong.
-- Iain Clarke
[My articles]
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How do you go about randomly assigning alternating vowels and consonants? I have created arrays for each but can not determine the way to alternate them. Yes it is homework I am looking for answers fast. Due tonight! I also have to create "x" number of random names and store them in an array called "first". I also have to do it for last, but once i can get the first to work then the last name should be identical with some minor changes. thanks for you response by the way. i have not been able to get anything from anyone, especially my prof.
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Chuck Vought wrote: How do you go about randomly assigning alternating vowels and consonants? I have created arrays for each but can not determine the way to alternate them.
That's simple, Stuart already provided the way, see [^]. The idea is:
the index of a loop takes alternatively even and odd values, you should choose a consonant whenever the loop index is even (a vowel whenever it is odd). To test for evenness (or oddness) use the modulus operator % this way: (i%2) (it returns 0 whenever i is even and 1 whenever i is odd).
As about assigning names to an array, what is your doubt?
If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.
This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong.
-- Iain Clarke
[My articles]
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