[newbie] [error] must declare a body because it is not marked abstract, extern, or partial - C# Discussion Boards

Re: Object reference not set to an instance of an object.?

1-Jan-09 2:08

hung1984 wrote:
Command[] Response = new Command[200];

This creates an array of 200 instances of null. Each must be created before you assign values to it.

Response[i] = new Command();

Christian Graus

Driven to the arms of OSX by Vista.

dec821-Jan-09 2:10

dec82

1-Jan-09 2:10

they are already created here:
foreach (XmlNode commandnode in List)
{
int i = int.Parse(commandnode.Attributes["value"].InnerText);
Response[i] = new Command();
HartResponses[i].Number = i;
.............

Re: Object reference not set to an instance of an object.?

Christian Graus1-Jan-09 2:36

Re: Object reference not set to an instance of an object.?

1-Jan-09 2:36

Any code that assumes a child node exists, is bad code. I guess this attribute is not always there.

A good way to debug this code is to break it up into as many lines as possible, and see which line blows up. The debugger is also a powerful tool.

Christian Graus

Driven to the arms of OSX by Vista.

dec821-Jan-09 2:59

dec82

1-Jan-09 2:59

i use it cause my xml file surely have the node named Response. But why the error started with Response[1]?

Re: Object reference not set to an instance of an object.?

Christian Graus1-Jan-09 3:08

Re: Object reference not set to an instance of an object.?

1-Jan-09 3:08

I assume because that's the one that doesn't have the attribute. Hard to say, I don't see your XML, and you don't say if you did what I told you to do to work out the exact problem.

Christian Graus

Driven to the arms of OSX by Vista.

dec821-Jan-09 3:58

dec82

1-Jan-09 3:58

thanks a lot. I think there's some mistake with my xml file Big Grin | :-D

Crystal Report Designer

spiritboy31-Dec-08 23:19

spiritboy

31-Dec-08 23:19

high i am learning crystal reports and have looked at some articles here to find how to create a crystalviewer, after i add a new item(Crystal Report item) i can not see the designer! i just have "myreport.rpt" and "myreport.cs" in my solution explrr. when i double click on "myreport.rpt" it shows me some hex codes and when i d-click on "myreport.cs" it tells me to drag item from toolbox!
how i can launch the designer and add tables and etc....?

[newbie] [error] must declare a body because it is not marked abstract, extern, or partial

jon-8031-Dec-08 23:01

jon-80

31-Dec-08 23:01

I'm trying out remote debugging from a WinXP Pro machine to a Win 2003 Server machine (where the source code is deployed).

When I try to compile from Visual Studio 2008, the following error is displayed:
Error 1 'CaseTrak.Activities.StatusUpdater.CTSetCaseReviewStatus(string, int)' must declare a body because it is not marked abstract, extern, or partial z:\Projects\CaseTrak.Activities\CaseTrak.Activities\StatusUpdater.cs 37 21

<code>
public bool CTSetCaseReviewStatus(string sCaseID, int iStatus)   //{ //get; }
<code>
</code></code>

Resolution (http://msdn.microsoft.com/en-us/library/bb397743.aspx[^])suggests to me that get and set methods have to be set for the variable type, however, it does not seem to fit within the context.

Any ideas?

// cs0840.cs
// Compile with /target:library
using System;
class Test
{
public int myProp { get; } // CS0840

// to create a read-only property
// try the following line instead
public int myProp2 { get; private set; }

}

using System;
using System.ComponentModel;
using System.ComponentModel.Design;
using System.Collections;
using System.Drawing;
using System.Workflow.ComponentModel.Compiler;
using System.Workflow.ComponentModel.Serialization;
using System.Workflow.ComponentModel;
using System.Workflow.ComponentModel.Design;
using System.Workflow.Runtime;
using System.Workflow.Activities;
using System.Workflow.Activities.Rules;
using CaseTrak.WebServices;

namespace CaseTrak.Activities
{
	public partial class StatusUpdater: SequenceActivity
	{
		public StatusUpdater()
		{
			InitializeComponent();
		}

        protected override ActivityExecutionStatus Execute(ActivityExecutionContext executionContext)
        {
            try 
            {
               
            }
            catch  (Exception ex)
            {
            
            }
            return ActivityExecutionStatus.Closed;
        }

        public bool CTSetCaseReviewStatus(string sCaseID, int iStatus);

	}

    
}

Jon

Re: [newbie] [error] must declare a body because it is not marked abstract, extern, or partial

beatles169231-Dec-08 23:25

beatles1692

31-Dec-08 23:25

Hi As you know a class can have fields,methods,properties and events.In general ,methods are behaviors and fields are attributes of a class.(Properties are some special methods to control accessing to the fields according to the encapsulation rule) therefore if there's a behavior (method or property) it should be implemented (or as the exception says should have a body using brackets) unless it's either an abstract method in an abstract class that it's inheritor should implement it and thus it should not have a body or an external method (a placeholder for a windows API method)
The problem here is that you have a CTSetCaseReviewStatus method that has no body.You can change it like this:

public bool CTSetCaseReviewStatus(string sCaseID, int iStatus)
{
//Do something and return its result
}

adding 2 hashtable

tejesh12331-Dec-08 20:48

tejesh123

31-Dec-08 20:48

hi friends

How do i add/merge 2 hashtables into third hashtable

Tejesh

Re: adding 2 hashtable

Christian Graus1-Jan-09 2:09

Custom control's property problem

1-Jan-09 2:09

If there's no method for this, you can iterate over the Keys and use those to copy the values in.

Christian Graus

Driven to the arms of OSX by Vista.

Re: adding 2 hashtable

User 66581-Jan-09 2:56

User 6658

1-Jan-09 2:56

If you use .NET 3.5 then you can use the Union method:

Dictionary<int,> dicA = new Dictionary<int,>();
dicA.Add(1, 10);
dicA.Add(2, 20);
dicA.Add(3, 30);

Dictionary<int,> dicB = new Dictionary<int,>();
dicB.Add(3, 35);
dicB.Add(4, 40);
dicB.Add(5, 50);

var newDic = dicA.Union(dicB);

regards

modified 12-Sep-18 21:01pm.

Xmen Real 31-Dec-08 18:35

31-Dec-08 18:35

i have developed a custom control that have some property to show/hide its child controls. When i set their Visible prop to False the get Hide. But when i run it or just reopen that control they appear again. Any solution ?

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beatles169231-Dec-08 23:28

beatles1692

31-Dec-08 23:28

Hi Can you send us some code ?

Xmen Real 31-Dec-08 23:31

31-Dec-08 23:31

didnt think it would need, well here is it.

public bool ShowThing
{
get { return picturebox1.Visible; }
set { picturebox1.Visible = value; }
}

Pedram Behroozi1-Jan-09 0:49

Pedram Behroozi

1-Jan-09 0:49

Hi,
Unfortunately I couldn't get you. What do you mean by Run It? Or Reopen It?
When you create a new instance of a Control (User Controls too) its properties got their default values (I hope I could tell it right).

I died as a mineral and became a plant,
I died as plant and rose to animal,
I died as animal and I was Man.
Why should I fear? When was I less by dying?
-- Rumi[^]

My blog

Xmen Real 1-Jan-09 0:55

1-Jan-09 0:55

i know that...'run it' mean run the application

Pedram Behroozi1-Jan-09 1:21

Pedram Behroozi

1-Jan-09 1:21

Ummm... So you set the ShowThing value to false but when you run your application they're visible?
Maybe you changed some values in PropertyBinding or DataBinding. Make sure their values are set to none.
I have a UC like you. It has a property named TextMultiLine, here:

public partial class LabeledTextBox : UserControl
{
    public bool TextMultiLine
    {
        get { return txtText.Multiline; }
        set { txtText.Multiline = value; }
    }
}

And I have no problem with it:

public partial class frmMain : Form
{
    public frmMain()
    {
        InitializeComponent();
        LabeldTextBox ltxt = new LabeledTextBox();
        
        ltxt.TextMultiLine = true; // And it works in runtime and everywhere else
    }
}

I think your problem is in somewhere else. I hope you can find it Smile | :)

I died as a mineral and became a plant,
I died as plant and rose to animal,
I died as animal and I was Man.
Why should I fear? When was I less by dying?
-- Rumi[^]

My blog

Xmen Real 1-Jan-09 1:51

1-Jan-09 1:51

dude, its works after InitializeComponent() called but not before. Dunno whats the cause

Eddy Vluggen2-Jan-09 2:07

Eddy Vluggen

2-Jan-09 2:07

Do you by any chance have a private field that looks like this?

private bool ShowThing = true;

I are troll Smile | :)

Xmen Real 2-Jan-09 3:22

2-Jan-09 3:22

it wont showup in propertygrid

Eddy Vluggen2-Jan-09 21:53

Eddy Vluggen

2-Jan-09 21:53

[Browsable(true)]
public bool TextMultiLine
{
        get { return txtText.Multiline; }
        set { txtText.Multiline = value; }
}

This?

I are troll Smile | :)

Xmen Real 2-Jan-09 22:02