C / C++ / MFC

pl_kode wrote:

At present I am hardcoding it like..

char path[]="c:\properties\file.properties"

class A
{
public:
virtual void show(){cout<<"Class A invoked"};
}
class B
{
public:
virtual void show(){cout<<"Class B invoked"};
}
class C: public A, public B
{
}

main()
{
C* ptr = new A;
ptr->show(); // "Class A invoked" will be printed
C* ptr1 = new B;
ptr1->show(); // "Class B invoked" will be printed
}

Muhammad Zeeshan wrote:

A class is inheritting from 2 base classes and both the base classes have a function/method with the same name.

Base1       Base2
  \           /
   \         /
        \       /
     Derived

Muhammad Zeeshan wrote:

From the object of the child class how we can call a function of the one base class.

Derived DerivedObject;
DerivedObject.Base1::CommonFunction();

// If its allocated as pointer.
Derived* pDerivedObject = new Derived;
pDerivedObject->Base1::CommonFunction();

lahom wrote:

if i have any kind of operation in one dialog and the result should appear on another dialog

OnPressButton ()
{
  //do your calculation
  CSecondDialog myDialog;
  myDialog.m_varResult = your_calculation_result;
  int nReturn = myDialog.DoModal ();

}

Greetings.
--------
M.D.V.

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