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hey any one can help me in making a list box control as muliple columns.
with this code its looking nasty.
UserList.Items.Add(pcon.dr1(0) & "|" & pcon.dr1(1) & "|" & pcon.dr1(2))
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I was told before I think on this forum that you can't put two columns in a listbox control, I think you can join two different listboxes together but you cant use two columns in one
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www.codeproject.com/KB/webforms/MCEnhancedListBoxControl.aspx
hey in above exapmle i want to assign a datareader to get list box items.
and when transfering like in above page can i transfer datavaluefield ? there i can transfer only selected text only. i want to transfer datavaluefield also can any one suggest.
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I thought it was already taken the datavalue field because it is using lstBox.SelectedItem.Value.ToString();
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hi
i am using rich text format in our project
and want to store data in html format
hi every body
but at storing time its taking some spical charcter
<p>hi</p><p><font color="#ff0000"><strong>every boby</strong> </font></p>
if any one know plz help me
thanks
krishna veer singh
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I don’t know your exact requirement. May be you are looking for the Server.HtmlDecode function.
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acctully i wamt to store data in html format
becoz when i retrive this data it will shown in formated way
krishna veer singh
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hai
my code:
Response.Clear();
Response.AppendHeader("Content-Disposition","attachment; filename=" + filename);
Response.AppendHeader("Content-Length", filename.Length.ToString());
Response.ContentType = "text/plain"; //if pdf file "application/pdf"
string strMapPath = Server.MapPath("~FolderName/filename);
FileStream fs = new FileStream(strMapPath, FileMode.Open,FileAccess.Read, FileShare.ReadWrite);
long bytesToGo;
int bytesRead;
Byte[] buffer = new byte[1048576];
bytesToGo = fs.Length;
while (bytesToGo > 0)
{
bytesRead = fs.Read(buffer, 0, 1048576);
Response.OutputStream.Write(buffer, 0, bytesRead);
Response.Flush();
bytesToGo -= bytesRead;
}
fs.Close();
Response.End();
my problem is downloaded file .sql file[size:4mb], which was not fully downloaded, it partially downloaded.i.e the download file doesn't show the full content it shows only 10 or 15 lines.
if anyone known about this,help me
Thanks in Advance
Known is a drop , Unknown is an Ocean
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Can you explain a bit more your problem, what do you mean by
ganeshMohan wrote: my problem is downloaded file .sql file[size:4mb], which was not fully downloaded, it partially downloaded.i.e the download file doesn't show the full content it shows only 10 or 15 lines.
Whats the code above for, is it from the downloaded file?
Where are you downloading the file from?
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Try Response.WriteFile or Response.TransmitFile.
Vasudevan Deepak Kumar
Personal Homepage
Tech Gossips
A pessimist sees only the dark side of the clouds, and mopes; a philosopher sees both sides, and shrugs; an optimist doesn't see the clouds at all - he's walking on them. --Leonard Louis Levinson
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wild guess, isn't problem in this line:
Response.AppendHeader("Content-Length", filename.Length.ToString());
where you are saying that content of the response is as long as length of the filename?
Pilo
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basically my page has 10 controls, and is there javascript to validate these, meanwhile AjaxToolkit:autoCompleteExtendender is there for some controls, in this case javascript shows the error "Object does't support this method" (Javascript error), Is there anything wrong with these...
can any one help me?
Thank you
DVSR Murty
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hmm..there is nothing wrong in using javascript in AJAX enabled aspx pages...also as you are using AJAX u may be rendering only a part of the page and for that if javascript has to be enabled u have to use ScriptReference
eg:
<asp:scriptmanager id="SampleMngr" runat="server">
<scripts>
<asp:scriptReference path="SampleScript.js" />
</scripts>
</asp:scriptmanager>
.....
.....
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hi
friends few days back i have posted the question of cross browser compatibility got answers too (sending only the part of html which browser supports)
sorry to ask again
I am having 4 table each with 4 textboxes and 4 labels
on the next button click i am hiding one table and showing second
Now these things work rite in I.E please suggest how to make it working in Firefox..?
i am struck with these .... please please tell me how to solve it
i know this is a hectic question for people who have worked on these things many times still i am desperately waiting for replys
Thank You
Dont Get Paid for the Hours you worked, Get Paid for the Work You Have Done in an Hour.
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ALT + F4 wrote: on the next button click i am hiding one table and showing second
Are you using javascript for that ?
Could you post your javascript code ?
Check this code might helpfull
to show
document.getElementById(groupid).style.display="";
document.getElementById(groupid).style.visibility="visible";
to hide
document.getElementById(groupid).style.display="none";
document.getElementById(groupid).style.visibility="hidden";
It would be better if you explain how you are using javascript code
Thanks and Regards
Sandeep
If If you look at what you do not have in life, you don't have anything,
If you look at what you have in life, you have everything... "
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If you are hiding through javascript then possibly u are using the statements not supported by Firefox...i mean Firefox dom doesn't support all the elements as IE supports..so u have to debug each statement in your javascript and find where the error is there 
.....
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all the things are working fine ...but in firefox controls are moving towards the menu-bar...i mean to say touching top..of the windows they are loosing there positions ...how to solve it
Dont Get Paid for the Hours you worked, Get Paid for the Work You Have Done in an Hour.
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ohhh if that is the problem...
simply create a main table and keep the four tables that you have inside it according to the need. Using rows and columns in tables gives you a fixed UI
i hope that helps! 
Aditya 
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are you getting any errors on the java error console in firefox? If so, post the error messages that you are getting... this would help us to help you better.
Aditya
Aditya
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NO ERRORS ! only Display Problem
Dont Get Paid for the Hours you worked, Get Paid for the Work You Have Done in an Hour.
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If your css code isn't too large can you post it so we can try and replicate the error.
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thank u .netman . but here i am using only style associated with the control ..not an external one ...
should i use External Style sheet ?
Dont Get Paid for the Hours you worked, Get Paid for the Work You Have Done in an Hour.
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OK
can you post the code for the controls because it must be the style you have set for them which is causing them to appear at the top of the page
I dont think you have to use an external style sheet although its usually better coding practice to do so
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<table id="layer1" bgcolor="#ffffff" style="z-index: 105; left: 140px; width: 575px;
position: absolute; top: 168px; height: 300px" bordercolor="#99cc00">
http://www.rakshanllc.com/webbooking/booking.aspx
u can see the difference in IE and FireFox
Dont Get Paid for the Hours you worked, Get Paid for the Work You Have Done in an Hour.
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