printing url [modified] - C# Discussion Boards

My IM C# project, is an Instant Messenger C# project that my supervisors gave me for my training, it's because all of them are JAVA developers and i'm the only who practices C# .NET i can't get enough help. maybe they just want me to practice independent programming (if it's what it is...)
the difference is that (for me..), that a normal C# project doesnt use importing dll's much and it uses it's own capabilities to deal with the project requirements. mine is much complicated (for my own programming experience so far.) i'm almost finished with the form designs, and it's function and all. it's just that i'm stuck on the importing the dll from the unmanaged VC++6. it's just that i cant fully understand on my own how to solve the "Entry Point" part. all i know is that the "Entry Point" is the function inside the dll that i imported. i just cant figure it out how to indentify although i know what's the function is.
hope this will help on clearing some things regarding on my question.
regards... Smile | :)

In the land of the blind, the one-eyed man is the king.[^]

Hello
I know such a task would be irritating to someone who isn't experienced in C#, but don't giveup yet.
There are many ways to use unmanaged dlls in your application, some hints are:
1- If you got the source, you may convert it to Visual Studio 2005 project -or wahtever you're using-, then compile it with the /CLR option. This way your Dll will be managed, and you can reference it like any other assimbly. You can find this option fomr the projects properties.

2- If it's a COM dll, you can reference it directly!! What would be the problem then??

3- If your Dll has only functions, you might want to try the DllImport attribute, check it out in the MSDN, I think it has an EntryPoint parameter

By the way: the error you mentioned in the original question, you said the event is ButtonClick, and it doesn't match your delegate. I thought they both were written by you in your C# program?? What does the Dll got to do with that??! Confused | :confused:

When making events don't try to write it manually, just click on the button in the form, & it will be generated automatically.

I hope that was useful Smile | :)

My problem is: i have a dropdownlist1, a button1, lable1, label2; when i click into dropdownlist1 and select a number that i want, the page will re-draw dynamic TextBoxes, these TextBoxes allow u type data into. when i click button1, data in these TextBoxes is saved.
my code:
public class WebForm1 : System.Web.UI.Page
{
protected System.Web.UI.WebControls.DropDownList DropDownList1;
protected System.Web.UI.WebControls.Label Label1;
protected System.Web.UI.WebControls.Label Label2;
protected System.Web.UI.WebControls.Button Button1;

Label[] lb = new Label[7];
TextBox[] te = new TextBox[7];
string[] s={"a", "b", "c", "d","e","f", "g", "h"};
protected System.Web.UI.WebControls.Panel Panel1;
int so=0;
private void Page_Load(object sender, System.EventArgs e)
{
Panel1.Width = 300;
}
#region Web Form Designer generated code
override protected void OnInit(EventArgs e)
{
//
// CODEGEN: This call is required by the ASP.NET Web Form Designer.
//
InitializeComponent();
base.OnInit(e);
}

///

/// Required method for Designer support - do not modify
/// the contents of this method with the code editor.
///

private void InitializeComponent()
{
this.DropDownList1.SelectedIndexChanged += new System.EventHandler(this.DropDownList1_SelectedIndexChanged);
this.Button1.Click += new System.EventHandler(this.Button1_Click);
this.Load += new System.EventHandler(this.Page_Load);

}
#endregion
private void DropDownList1_SelectedIndexChanged(object sender, System.EventArgs e)
{
so=Convert.ToInt32(DropDownList1.SelectedValue);
for(int i=0;i

i want to read multiple pictres and to store their colors pixels value into matrix.
i need this matrix 3d...as the first 2d to the dimensions of the pictures and the third dimension to represent the number of the picture(i.e 1st picture , 2nd picture .......)
how can i do that?

haitham

How about a 3D array:

ColorPixel[,,] colorPix = new ColorPixel[xPos, yPos, picIndex];

Best,
Jun

3D is what i want but u mean by "colorpixel" a type or u wrote it as example for any other type
cause i searched for it in the msdn and i didn`t find it in the msdn
thanks for ur reply jun.

haitham

eng:haitham wrote:
u wrote it as example for any other type

Yes, whatever type (e.g., int) you want "ColorPixel" to be.

Best,
Jun

i tried to use these lines of codes:

[CODE]
public class PrintingExample : System.Windows.Forms.Form
{
private System.ComponentModel.Container components;
private System.Windows.Forms.Button printButton;
private Font printFont;
private StreamReader streamToPrint;

public PrintingExample() : base()
{
// The Windows Forms Designer requires the following call.
InitializeComponent();
}

// The Click event is raised when the user clicks the Print button.
private void printButton_Click(object sender, EventArgs e)
{
try
{
streamToPrint = new StreamReader
("C:\\My Documents\\MyFile.txt");
try
{
printFont = new Font("Arial", 10);
PrintDocument pd = new PrintDocument();
pd.PrintPage += new PrintPageEventHandler
(this.pd_PrintPage);
pd.Print();
}
finally
{
streamToPrint.Close();
}
}
catch(Exception ex)
{
MessageBox.Show(ex.Message);
}
}

// The PrintPage event is raised for each page to be printed.
private void pd_PrintPage(object sender, PrintPageEventArgs ev)
{
float linesPerPage = 0;
float yPos = 0;
int count = 0;
float leftMargin = ev.MarginBounds.Left;
float topMargin = ev.MarginBounds.Top;
string line = null;

// Calculate the number of lines per page.
linesPerPage = ev.MarginBounds.Height /
printFont.GetHeight(ev.Graphics);

// Print each line of the file.
while(count < linesPerPage &&
((line=streamToPrint.ReadLine()) != null))
{
yPos = topMargin + (count *
printFont.GetHeight(ev.Graphics));
ev.Graphics.DrawString(line, printFont, Brushes.Black,
leftMargin, yPos, new StringFormat());
count++;
}

// If more lines exist, print another page.
if(line != null)
ev.HasMorePages = true;
else
ev.HasMorePages = false;
}

// The Windows Forms Designer requires the following procedure.
private void InitializeComponent()
{
this.components = new System.ComponentModel.Container();
this.printButton = new System.Windows.Forms.Button();

this.ClientSize = new System.Drawing.Size(504, 381);
this.Text = "Print Example";

printButton.ImageAlign =
System.Drawing.ContentAlignment.MiddleLeft;
printButton.Location = new System.Drawing.Point(32, 110);
printButton.FlatStyle = System.Windows.Forms.FlatStyle.Flat;
printButton.TabIndex = 0;
printButton.Text = "Print the file.";
printButton.Size = new System.Drawing.Size(136, 40);
printButton.Click += new System.EventHandler(printButton_Click);

this.Controls.Add(printButton);
}

// This is the main entry point for the application.
public static void Main(string[] args)
{
Application.Run(new PrintingExample());
}
}

replacing :

streamToPrint = new StreamReader
("C:\\My Documents\\MyFile.txt");
try

with :

streamToPrint = new StreamReader
("http://www.google.com");
try

but it has an error message : " URI format not supported"

so what must i do so that i can print url format?

[/CODE]
-- modified at 22:21 Sunday 25th June, 2006

Wow, what a long post... OMG | :OMG:

Anyway, StreamReader class can't read remote web pages by itself -supposingly-. You should check the System.Net namespace for classes that read html pages -eg. HttpWebRequest-

By the way, this way you will print the Html of the page. Why don't you check the WebBrowser component? It has a Print() method.

hi i want to envrypt/decrypt data (for example video stream) on the fly and play it ?
thanks

Take a look at the CryptoStream class, acts just like a stream only downside is that I don't think it will finish encrypting or decrypting until the stream is closed (I might have got this confused with the compressor streams such as Gzip but I'm not sure).

Formula 1 - Short for "F1 Racing" - named after the standard "help" key in Windows, it's a sport where participants desperately search through software help files trying to find actual documentation. It's tedious and somewhat cruel, most matches ending in a draw as no participant is able to find anything helpful. - Shog⁹

Ed

When I see the application which developed by other people are so cool ,while I can not achieve.Who can tell me how to make the application more cool. Smile | :)

No begin no end.

Hello
The "cool" word is a bit ill descriptive. Simply the answer to your question is another question:
What did you see in those applications that made you say they are "cool"?
If you already know that answer, then do the same in your applications, but of course in an innovative way -not imitative, ie. don't just copy ideas-

Some hints that might be useful:
1- Your user interface must be compact, user friendly -ie. relaxing to the eye at first look-, yet efficient
2- Your application must have a "genuine" idea -Perhaps this is the most important thing-
3- Your application must be easy to learn, and for advanced features, there should be tutorials or "easy to get" helps
4- Preferably support both beginner, and advanced users

These are not -must follow- rules, just few hints.

See if we can come up with right phrases for a good application based on your hints:

1 - User Friendly
2 - Creative
3 - Intuitive
4 - Versatile

Best,
Jun

Nice!!;)
I like the "Shortest distance between two points is a straight line" thinking of yours Jun.

http://msdn2.microsoft.com/en-us/library/system.threading.threadstart.aspx[^]

Found by Googling. Roll eyes | :rolleyes:

"Just about every question you've asked over the last 3-4 days has been "urgent". Perhaps a little planning would be helpful?"
Colin Angus Mackay in the C# forum

led mike

led mike wrote:
http://msdn2.microsoft.com/en-us/library/system.threading.threadstart.aspx[^]

Found by Googling.

Talking to yourself? Big Grin | :-D

Scottish Developers events:
* .NET debugging, tracing and instrumentation by Duncan Edwards Jones and Code Coverage in .NET by Craig Murphy
* Developer Day Scotland: are you interested in speaking or attending?
My: Website | Blog

Colin Angus Mackay wrote:
Talking to yourself?

second time last week someone whined "can't find it on google" 20 seconds later... there it is on my google results. You really gotta wonder when they can't even use a search engine maybe they should consider a different field. Unsure | :~

Hello guys,

I have the following Regular Expression, I want to convert it from PHP to C#.

$aVar = preg_replace("/[\r\n]{1,2}(.+)\#(.*)[\r\n]{1,2}/U", "$myRightVar\\1$myCenterVar\\2$myLeftVar\r", $aVar);

( http://www.php.net/preg_replace )

I tried a lot but I failed. Can you please help me. Thanks.

The Regex is okay, at least it compiles and Expresso doesn't complain. What shall it match actually?

regards

modified 12-Sep-18 21:01pm.

I'm new to C#. This is the first time I'm using Regular expression. Can you give me the complete C# tag please?

What the code does is taking any line that contains # charachter and add $myRightVar at the beginning of the line then replace # with $myCenterVar and add $myLeftVar at the end of the line.

Download Expresso. You'll find it very helpful. And it generates C# code for you.

http://www.ultrapico.com/Expresso.htm[^]

Kevin

string regex=@"[\r\n]{1,2}(.+)\#(.*)[\r\n]{1,2}";
string replace=String.Format("{0}\\1{1}\\2{2}\r",myRightVar,myCenterVar,myLeftVar);

string output=Regex.Replace(input,regex,replace);

Haven't got VS in front of me, but this (hopefully) should work.

Graham.

-- modified at 15:34 Sunday 25th June, 2006

It's almost working... the problem is I'm NOT getting the old left text and the old right text shown. I'm getting \1 and \2.

What's wrong?

Many thanks.

This is a different approach, maybe it works for you?

string regex = @"[\r\n]{1,2}(.+)\#(.*)[\r\n]{1,2}";

Match m = Regex.Match(input, regex);
if (m.Success)
{
	string output = String.Format("{0}{1}{2}{3}{4}\r", myRightVar, m.Groups[1], myCenterVar, m.Groups[2], myLeftVar);
	Console.WriteLine(output);
}

Probably this might also work, it's way shorter:

string output2 = Regex.Replace(input, regex, String.Format("{0}$1{1}$2{2}\r", myLeftVar, myCenterVar, myRightVar));

regards

modified 12-Sep-18 21:01pm.