C / C++ / MFC

m_myList.ModifyStyle(0, LVS_SINGLESEL);

m_myList.ModifyStyle(LVS_SINGLESEL, 0);

int main()
{
  int *ptr[2];
  for (int i = 0; i < 2; i++) {
    ptr[i] = NULL;
  }
  //...
  if (ptr[0] == NULL) {
    cout << "this is empty" << endl;
  }
}

int* ptr[2]={0};
cout << ptr[0] << endl;
cout << ptr[1] << endl;

string input;
char *driver;

cout << "Please input the driver's name : ";
cin >> input;

driver = new char[input.length() + 1];
strcpy(driver, input.c_str());
driver[input.length()] = 0;

cout << driver << endl;

neodeaths wrote:

i tryed it and it works thanks and i understand it too

but i wanna know wht do i need this?
driver[input.length()] = 0;

y shld assigh to 0??

Nishant Sivakumar wrote:

C/C++ strings are considered to be 0-terminated. If you don't terminate your string with a 0, any function that expects a 0-terminated string would run into issues.

Roland Pibinger wrote:

Yes, but strcpy also copies the teminating '\0'.

neodeaths wrote:

driver = new char[strlen(input)+1];

Britley wrote:

I have macros LOG1 to LOG5 for logging that aid debugging in my application. However with increased logging my application is effectively getting slowed down, so much to the extent that that application now takes 100 times longer.

<br />
void  _log(const char *format_str, ...);<br />
#define LOG1 if (logleve >= 1) _log<br />
#define LOG2 if (logleve >= 2) _log<br />
#define LOG3 if (logleve >= 3) _log<br />