C# Discussion Boards - CodeProject

30-Mar-12 8:44

how can we use #pragma omp directive in c# vs 2010??

RobCroll30-Mar-12 14:24

RobCroll

30-Mar-12 14:24

Here is the documentation #pragma warning (C# Reference)[^]

"You get that on the big jobs."

KUNWAR99930-Mar-12 22:23

30-Mar-12 22:23

its taking more execution time than sequential code.. any sol?? Frown | :(

Richard MacCutchan30-Mar-12 23:26

Richard MacCutchan

30-Mar-12 23:26

That is not possible; #pragma is a compiler directive and has nothing to do with execution speed.

Unrequited desire is character building. OriginalGriff
I'm sitting here giving you a standing ovation - Len Goodman

KUNWAR99930-Mar-12 23:39

30-Mar-12 23:39

but i want to reduce the execution time of a loop by making it parllel...

for(int i=0;i<100;i++)
{
Console.WriteLine(i);
}
thatwhy i used pragma directive..
# prgma omp parllel
for(int i=0;i<100;i++)
{
Console.WriteLine(i);
}
but its increse the time instead of reducing.. Frown | :(

any sol for this??

Richard MacCutchan31-Mar-12 0:03

Richard MacCutchan

31-Mar-12 0:03

This has nothing to do with your original question, and I have already answered with a suggestion here[^].

KUNWAR999 wrote:
# prgma omp parllel

What is this supposed to mean?

Unrequited desire is character building. OriginalGriff
I'm sitting here giving you a standing ovation - Len Goodman

Luc Pattyn31-Mar-12 3:49

Luc Pattyn

31-Mar-12 3:49

Here[^] you go. Warning: it is a different world altogether.

Smile | :)

Luc Pattyn [My Articles] Nil Volentibus Arduum

Richard MacCutchan31-Mar-12 4:18

Richard MacCutchan

31-Mar-12 4:18

Yes, I did discover that in the C++ compiler. My question was to get OP to explain what he/she thought it was, in terms of C#.

Unrequited desire is character building. OriginalGriff
I'm sitting here giving you a standing ovation - Len Goodman

Pete O'Hanlon31-Mar-12 4:03

Pete O'Hanlon

31-Mar-12 4:03

A few points. That pragma is for C/C++. If you want to have the sequence in order, you shouldn't try to turn it parallel as there is no guarantee of order of execution in parallel processing. If this isn't an issue, why not use the Task Parallel Library.

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Change the packet IP (source or destination) with Pcap.net

harold aptroot31-Mar-12 4:03

harold aptroot

31-Mar-12 4:03

You can't, so there is no answer to "how". The standard C# compiler does not support OpenMP.

falukky30-Mar-12 1:10

falukky

30-Mar-12 1:10

i am using Pcap.net to send packets using send buffer with Wireshark file (pcap extension) and i want to do some packet manipulation e.g change the packet IP, but after send the packet again the packet looks corrupt with checksum bad and malformed TCP

// Allocate a send buffer
using (PacketSendBuffer sendBuffer = new PacketSendBuffer((uint)capLength))
{
    // Fill the buffer with the packets from the file
    int numPackets = 0;
    Packet packet;
    while (inputCommunicator.ReceivePacket(out packet) == PacketCommunicatorReceiveResult.Ok)
    {
        //sendBuffer.Enqueue(packet);
        IpV4Layer ipLayer = (IpV4Layer)packet.Ethernet.IpV4.ExtractLayer();
        EthernetLayer ethernet = (EthernetLayer)packet.Ethernet.ExtractLayer();
        var payload = packet.Ethernet.Payload.ExtractLayer();
        IpV4Address newIpv4 = new IpV4Address("17.18.19.20");
        ipLayer.Destination = newIpv4;
        Packet newPacket = PacketBuilder.Build(DateTime.Now, ethernet, ipLayer, payload);
        sendBuffer.Enqueue(newPacket);
        ++numPackets;
    }

    outputCommunicator.Transmit(sendBuffer, isSync); //Transmit the queue
}

Re: Change the packet IP (source or destination) with Pcap.net

Richard Andrew x6430-Mar-12 4:42

Richard Andrew x64

30-Mar-12 4:42

And your question is?

The difficult we do right away...
...the impossible takes slightly longer.

Re: Change the packet IP (source or destination) with Pcap.net

falukky30-Mar-12 5:03

falukky

30-Mar-12 5:03

i have try something that i think is correct but in the line sendBuffer.Enqueue(newPacket) error received: Failed enqueueing to SendQueue

// Allocate a send buffer
using (PacketSendBuffer sendBuffer = new PacketSendBuffer((uint)capLength))
{
    // Fill the buffer with the packets from the file
    int numPackets = 0;
    Packet packet;
    while (inputCommunicator.ReceivePacket(out packet) == PacketCommunicatorReceiveResult.Ok)
    {
        //sendBuffer.Enqueue(packet);
        IpV4Layer ipLayer = (IpV4Layer)packet.Ethernet.IpV4.ExtractLayer();
        ipLayer.Destination = new IpV4Address("11.12.13.14");
        EthernetLayer ethernet = (EthernetLayer)packet.Ethernet.ExtractLayer();
        PayloadLayer payload = (PayloadLayer)packet.Ethernet.Payload.ExtractLayer();
        Packet newPacket = PacketBuilder.Build(DateTime.Now, ethernet, ipLayer, ipLayer, payload);
        sendBuffer.Enqueue(newPacket);
        ++numPackets;
    }

    outputCommunicator.Transmit(sendBuffer, isSync); //Transmit the queue
}

Re: Change the packet IP (source or destination) with Pcap.net

Richard Andrew x6430-Mar-12 5:08

Richard Andrew x64

30-Mar-12 5:08

Have you tried the PCap site? Don't they have a support forum?

The difficult we do right away...
...the impossible takes slightly longer.

Re: Change the packet IP (source or destination) with Pcap.net

falukky30-Mar-12 5:22

falukky

30-Mar-12 5:22

yes they have but the forum not so effective (lack of users)

digit roundoff

Member 823360130-Mar-12 0:46

Member 8233601

30-Mar-12 0:46

i have a float type of variable i.e float t1=200.36 and t2=300.62. now i want to roundoff these two variables to their nearest degit.

I want to show the information like this:
t1=200.36 roundoff=-0.36 total=200
t2=300.62 roundoff=+0.38 total=301

V.30-Mar-12 1:05

30-Mar-12 1:05

Look here:
Floor[^]
Ceiling[^]
Round[^]

Then you can take the difference of the original with the rounded value.
Hope this helps.

JF201530-Mar-12 1:28

JF2015

30-Mar-12 1:28

See this code to get the idea:

double t1 = 200.36;
double t2 = 300.62;
int t11 = (int)Math.Round(t1, 0);
int t21 = (int)Math.Round(t2, 0);
MessageBox.Show("t1=" + t1.ToString() + " roundoff=" + (t11 - t1).ToString("0.00") + " total=" + Math.Round(t1, 0).ToString());
MessageBox.Show("t2=" + t2.ToString() + " roundoff=" + (t21 - t2).ToString("0.00") + " total=" + Math.Round(t2, 0).ToString());

ProEnggSoft30-Mar-12 3:36

ProEnggSoft

30-Mar-12 3:36

I want to add the following

What is required when the number is half i.e. 200.5. Whether 200 or 201?
By default Math.Round follows
MidpointRounding.ToEven enumeration value.

double number = 200.5;
Console.WriteLine (Math.Round(number,0));
Console.WriteLine (Math.Round(number,0, MidpointRounding.AwayFromZero));
double number2 = 201.5;
Console.WriteLine (Math.Round(number2,0));
Console.WriteLine (Math.Round(number2,0, MidpointRounding.AwayFromZero));
//The output from the above code will be
//200
//201
//202
//202

So, if the next higher number is required always, when the value is half way, then
MidpointRounding.AwayFromZero is to be used.

modified 30-Mar-12 10:15am.

KUNWAR99930-Mar-12 7:17