C# Discussion Boards - CodeProject

Burt Harris9-Dec-02 21:47

Burt Harris

9-Dec-02 21:47

Take a look at the help topics under "Exposing .NET Framework Components to COM". I think that will cover what you need.

Burt Harris

Nick Parker10-Dec-02 4:20

Nick Parker

10-Dec-02 4:20

Burt Harris (msft) wrote:
Take a look at the help topics under "Exposing .NET Framework Components to COM".

MSDN Article link[^] Smile | :)

Nick Parker

Not everything that can be counted counts, and not everything that counts can be counted. - Albert Einstein

Rickard Andersson²⁰9-Dec-02 21:48

Rickard Andersson²⁰

9-Dec-02 21:48

You didn't create a DLL, you created an assembly. You cvan't use asseblies in VB6.

Rickard Andersson@Suza Computing
C# and C++ programmer from SWEDEN!
UIN: 50302279
E-Mail: nikado@pc.nu
Speciality: I love C#, ASP.NET and C++!

Kannan Kalyanaraman9-Dec-02 22:37

9-Dec-02 22:37

Hi,

It is possible to use .net assemblies in VB6 using Interop.
You need to run regasm tool with /tlb or /codebase option, so that it creates a wrapper for the .net assemblies to be called from COM.

Alternately you can directly reference MSCorLib / MSCorRe from VB6 and create instances of framework components(like HashTable or any other class). I dont have the sample with me right now, but DonBox demonstrated this sometime back in TechEd.

regards
Kannan

Rickard Andersson²⁰9-Dec-02 23:08

Rickard Andersson²⁰

9-Dec-02 23:08

Ooh!
Cool!

But does the .NET redistributable have to be installed on my customers computer??

Rickard Andersson@Suza Computing
C# and C++ programmer from SWEDEN!
UIN: 50302279
E-Mail: nikado@pc.nu
Speciality: I love C#, ASP.NET and C++!

Kannan Kalyanaraman9-Dec-02 23:13

9-Dec-02 23:13

Rickard Andersson wrote:
But does the .NET redistributable have to be installed on my customers computer??

Absolutely, its just a wrapper that is generated by the regasm dll, something like a proxy. The runtime kicks in once you start calling managed methods.

Cheers
Kannan Smile | :)

Rickard Andersson²⁰9-Dec-02 23:50

Rickard Andersson²⁰

9-Dec-02 23:50

Kannan Kalyanaraman wrote:
something like a proxy

<changed_subject>
Could you tell me where I could learn more about what a proxy is and how it works etc.?
I want to learn...
</changed_subject>

Rickard Andersson@Suza Computing
C# and C++ programmer from SWEDEN!
UIN: 50302279
E-Mail: nikado@pc.nu
Speciality: I love C#, ASP.NET and C++!

Kannan Kalyanaraman10-Dec-02 0:00

10-Dec-02 0:00

Well, I'm no expert here, but I can't recollect any specific resources as to deal with proxy/stub (in COM world).
You can refer to Don Box's Essential COM or Inside COM / DCOM for a thorough treatment on the subject.
In simpler terms Proxy might refer to a piece of code which helps to communicate between the provider / consumer.
I hope I'm not confusing you too much.

Cheers
Kannan Smile | :)

Kannan Kalyanaraman9-Dec-02 22:44

Question on SocketOptionName.ReceiveTimeout

9-Dec-02 22:44

hi $iva,

You cannot add reference to the dll (assembly) you have created in .net 'cause its not a proper COM dll, if you have a closer look, you can see that .net assembly doesnt have any COM specific mechanism to locate the particular DLL (there is no entry in the registry pointing to the location of the dll or does the other application know how to create an instance).

So, to call .net assembly from VB6 you need to do couple of things.
Create public interfaces and implement those interfaces in a class. Only public methods are visible to COM.
Run regasm tools against this assembly to make sure that other COM aware clients know how to create this COMponent and call those methods.
Refer msdn on Regasm and COM Interop.

Hope this helps.
Cheers
Kannan

yccheok9-Dec-02 17:50

yccheok

9-Dec-02 17:50

i obtain a socket through TcpListener using:
Socket mySocket = myListener.AcceptSocket() ;//myListener is TcpListener

sometimes, i realize that my program will halt at line:
int i = mySocket.Receive(bReceive,bReceive.Length,0) ;

hence, i was thinking to set a receive timeout option, my questions is
(1)is this the correct method
mySocket.SetSocketOption(SocketOptionLevel.Tcp, SocketOptionName.ReceiveTimeout, 1000)

i put SocketOptionLevel as SocketOptionLevel.Tcp, is it correct?

(2)what will happen when the program come to line
int i = mySocket.Receive(bReceive,bReceive.Length,0) ;

and after 1000 miliseconds and still have not received anything. where will the program execution go?

thank you.

regards
yccheok

Re: Question on SocketOptionName.ReceiveTimeout

grv57513-Dec-02 4:07

grv575

13-Dec-02 4:07

1) I'm using
socket = new Socket(AddressFamily.InterNetwork, SocketType.Stream, ProtocolType.Tcp);
socket.SetSocketOption(SocketOptionLevel.Socket, SocketOptionName.SendTimeout, 60000);
socket.SetSocketOption(SocketOptionLevel.Socket, SocketOptionName.ReceiveTimeout, 60000);
socket.SetSocketOption(SocketOptionLevel.Socket, SocketOptionName.ReceiveBuffer, 1024);
socket.SetSocketOption(SocketOptionLevel.Tcp, SocketOptionName.NoDelay, 1);

So I think it should be SocketOptionLevel.Socket. Found it elsewhere on google.

2) Set a breakpoint on that line and trace over it. It will either fire an exception or go to the next line. Don't quite remember. Check the return values for receive as well.

Running Application In Another Process Without Showing Console Window

yccheok9-Dec-02 17:49

yccheok

9-Dec-02 17:49

i try to run an console application through a programmatically created process. i dont want a new console command window to pop up during the process running. hence, i use the following code.

------
System.Diagnostics.ProcessStartInfo pi = new System.Diagnostics.ProcessStartInfo(Application.StartupPath+"\\EncodeFile.exe");
pi.CreateNoWindow = true;
p = new System.Diagnostics.Process();
p.StartInfo = pi;
p.Start();
------

however, the console command window still show up although i oledi set
pi.CreateNoWindow = true;

can anyone tell me the solution?

thank you.

regards
yccheok

Re: Running Application In Another Process Without Showing Console Window

Kannan Kalyanaraman9-Dec-02 22:47

Re: Running Application In Another Process Without Showing Console Window

9-Dec-02 22:47

try it with the compiler option /target:winexe

Cheers
Kannan

Richard Deeming10-Dec-02 0:03

Richard Deeming

10-Dec-02 0:03

You need to set the RedirectStandardInput, RedirectStandardOutput and RedirectStandardError properties of the <EDIT>ProcessStartInfo</EDIT> object to true. If you need to, you can then access the input and output of the console using the StandardInput, StandardOutput and StandardError properties.

E.g.:

ProcessStartInfo psi = new ProcessStartInfo();
psi.RedirectStandardInput = true;
psi.RedirectStandardOutput = true;
psi.RedirectStandardError = true;
psi.FileName = "Path to the exe";
Process p = Process.Start(psi);

"These people looked deep within my soul and assigned me a number based on the order in which I joined." - Homer

Problem with arraylist assignment

djkno39-Dec-02 13:59

djkno3

9-Dec-02 13:59

<br />
((Rectangle)mySquares[i]).X = <br />
((Rectangle)mySquares[i-1]).X;

I have an ArrayList of Rectangles and would like to update the X co-ordinate with the old one but this assignment generates a compiler error "The left-hand side of an assignment must be a variable, property or indexer"
yet the left hand side of this IS a property. Is there a reason for this? do I have to extract/assign the x co-ordinates in a for loop?

Rob Graham9-Dec-02 14:58

Rob Graham

9-Dec-02 14:58

If this is not already in a for loop, then how is the current value of i determined?
in any event, it will fail for i=0 since there is no element whose index = -1.
Perhaps we need a to see just a wee bit more of your code in order to help?;) Suspicious | :suss:

djkno39-Dec-02 21:18

djkno3

9-Dec-02 21:18

<br />
for (i = mySquares.Count - 1; i > 0; i--)<br />
{<br />
((Rectangle)mySquares[i]).X = <br />
((Rectangle)mySquares[i-1]).X;<br />
((Rectangle)mySquares[i]).Y = <br />
((Rectangle)mySquares[i-1]).Y;<br />
}<br />

I'm trying to update the x,y co-ordinates of the rectangles in the arrary in a Timer.Tic() method.

it tells me that my left operand has to be a property but is Rectangle.X not a property?

Burt Harris9-Dec-02 21:42

Burt Harris

9-Dec-02 21:42

Interesting, try this:

for (int i = mySquares.Count - 1; i > 0; i--) {
       Rectangle r1 = (Rectangle)mySquares[i];
       Rectangle r2 = (Rectangle)mySquares[i-1];
       r1.X = r2.X;
       r1.Y = r2.Y;
   }

Burt Harris

James T. Johnson10-Dec-02 0:58

James T. Johnson

10-Dec-02 0:58

Burt Harris (msft) wrote:
Rectangle r1 = (Rectangle)mySquares[i];
Rectangle r2 = (Rectangle)mySquares[i-1];

Unfortunately that won't work either.

The problem is that Rectangle is a value type so the modifications you are doing are being done to the unboxed value which is discarded. Instead, you should create a new Rectangle object and place it back in the collection.

for (int i = mySquares.Count - 1; i > 0; i--) 
{
    Rectangle r1 = (Rectangle)mySquares[i]; 
    Rectangle r2 = (Rectangle)mySquares[i-1];      
 
    mySquares[i] = new Rectangle(r2.X, r2.Y, 
        r1.Width, r1.Height);
}

[Edit]I should have posted this sooner instead of catching up on CP, Richard beat me to it :P[/Edit]
James

- out of order -

Richard Deeming10-Dec-02 0:13

Richard Deeming

10-Dec-02 0:13

Rectangle is a struct, so that probably won't work anyway, since you're changing the coordinates of an unboxed copy of your rectangle. Try something like:

for (i = mySquares.Count - 1; i > 0; i--)
{
    mySquares[i] = new Rectangle(
        ((Rectangle)mySquares[i-1]).Location,
        ((Rectangle)mySquares[i]).Size);
}

"These people looked deep within my soul and assigned me a number based on the order in which I joined." - Homer