C / C++ / MFC

void PassTrace(class *Pointer);

void PassTrace(Test *Pointer)

template <typename T>
void PassTrace<T *Pointer>
{
   // body of function
}

class myClass {
    // class members ...
};

void f(myClass *pointer)
{
     // function body 
}

int main()
{
    myClass c;
    // instantiate c's data members
    f(&c);  // call f with a pointer to object of type myClass
}

void BT_Utility_Library::PassTrace(class *)

class A { /* ... */ }
class B { /* ... */ }
class C { /* ... */ }

void f(class *ptr);

class C { /* ... */ }
int main()
{
   class C c1;
   C c2;
}

Salvatore Terress wrote:

using non C++ tool

charlieg wrote:

do you make extensive use of auto,

auto var = /*expression*/

Mircea Neacsu wrote:

IntelliSense will obligingly tell me that the compiler thinks it the variable type.

unordered_map<string, int> um{ {"foo", 1}, {"goo", 2}, {"boo",42}};

for (const auto & p : um)
{
  cout << p.first << ", " << p.second << "\n";
}

for (const pair<string, int> & p : um)
{
  cout << p.first << ", " << p.second << "\n";
}

Maximilien wrote:

when I declare a variable with auto, it will be typed accordingly and I cannot change the type.