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Thanks for your advice, Mark!
regards,
George
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size_t in unsigned but int is signed.
Steve
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Hi Stephen,
If I am converting size_t to unsigned int on 32-bit platform, are there any risks of data lost?
regards,
George
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It depends on how the conversion is done. Why not use size_t directly. If you can't perhaps unsigned int would be a closer match.
Steve
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Good idea Steve,
I will try to change the function signature (parameter type).
regards,
George
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Hi all;
I am (new to c++) trying to write a program which in part of it has a list of objects with a few variables.(pseudo code)
lets say:
class cObj
{
private:
int objNum;
string objName;
}
list<cobj> ListObj;
and we have three objects
obj1 ( onjNum =1 , ObjName = One)
obj2 ( onjNum =2 , ObjName = Two)
obj3 ( onjNum =3 , ObjName = Two)
and i want to search all the objects that have the name "Two".
result should be: &Obj2 and &Obj3 (or pointers)
how can i do it?
thanks a lot;
Beri
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If you store then in a vector, you can write a functor to do the search you are after and use the built in search algorithms.
Christian Graus - Microsoft MVP - C++
"I am working on a project that will convert a FORTRAN code to corresponding C++ code.I am not aware of FORTRAN syntax" ( spotted in the C++/CLI forum )
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thanks for you kind help!
i see, vector has a random access to any position.
but if i had to use a list(not only because i wrote a very long code :P)?
isn't there any option to check something like this:
lets say i have a function:
bool mysearch( string _objName)
{
int found = 0;
list::iterator iter;
iter = list.begin();
while(iter!=list.end())
{
if(iter.objName== _objName) //iter.objName is my problem - how to implement
found++ // get the times objName found
}
}
thanks a lot;
Beri
-- modified at 3:12 Saturday 28th July, 2007
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You should overload the == operator and use the find algorithm.
<br />
class cObj<br />
{<br />
int objNum;<br />
string objName;<br />
Below,you can actually have the int type as well that you can check for your "2" directly than passing it from an object. But in case you want to change the search condition sometime later, this doesnt help. Better pass the object and get the member from it.
<br />
bool operator == (const cObjSent)
{ <br />
return ((objNum==cObjSent.objNum));<br />
}<br />
}<br />
<br />
void main()<br />
{<br />
list <cObj> cObjObject;<br />
list <cObj> ::iterator cObj_iter;<br />
<br />
cObj_iter = find(cObjObject.begin(), cObjObject.end(), YOUR_COBJ_SEARCHOBJECT_HERE [Like for eg:your obj2]
);<br />
<br />
}<br />
<br />
He's become a household word in the Lounge. A whole new phraseology has evolved. Post a link or reply with a smiley and rose, and you've made a "Satipsism". So what? It's an interesting thing about the Internet, the evolution (as in change, not progress) of tone, quality, terminology, etc.
-Marc Clifton.
Best wishes to Rexx[^
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thanks a lot Marc!
May The Force Be With You...
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Hi all i want to make progress bar inside list control(report style). I have found various articles regarding this but they don't fulfil my requirements.
i have made a sdi application and that sdi window is divided with a vertical splitter controls in two parts.Each veiw is derived from CFormVeiw and have a list control in it.I want to make progress bar in my list control and that progress bar should start when i click a button on toolbar.
How to do this.....
Thanks in advance
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There are very good examples regarding this on codeproject i dont remember exact names but try something XListControl you will get it.
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Hi,
I want to write a program that when I input integer then the output will have commas if it has more than three digits. For example,
-2007 and 2000000 would be printed as -2,007 and 2,000,000 respectively..
# include <iostream>
# include <iomanip>
using namespace std;
int main ()
{
double digit;
cout <<" print it with comma "<< endl;
cin >> digit;
cout <<setiosflags(ios::fixed| ios::showpoint)<< setprecision(3) <<endl;
cout <<digit <<endl;
return 0;
}
dalmar mahamoud
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This really sounds like a homework problem. It is not that difficult to do.
"Real programmers just throw a bunch of 1s and 0s at the computer to see what sticks" - Pete O'Hanlon
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Hi all. Is it possible to have a program that executes under a different name under Windows? For example, program.exe executes under newprogramname.exe? Only reason why i asked is because i've always wandered how installation programs do it. Thanx in advance!
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I don't think it's possible. If it was, it would be a heck of a security vulnerability - unless the full path was placed somewhere, it would screw up every piece of anti-virus software in the world.
Install programs execute under the same name, as far as I know. It's just that they sometimes create temporary apps and run them as children.
Ninja (the Nerd)
Confused? You will be...
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I don't think it is possible, and could be suspicious...
"Real programmers just throw a bunch of 1s and 0s at the computer to see what sticks" - Pete O'Hanlon
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Yes!
I do not know what ‘Ninja-the-Nerd’ was talking about, but you can change the name all you want. What that has to do with installation I have no clue – so obviously I have no idea what you are talking about.
If you do not believe me – pick a program and rename it through the explorer and then run it.
The only problem that might occur is if that program was specified as the one used to handle a particular file format. If you change its name – then the system will not know what program to use (now), unless you tell it what the new name is.
Well actually – depending on the program – there could be other problems (rarely) if other programs depend on that one (a.k.a. file type handling). But let’s not go there or we will all end up with a head ache .
INTP
"Program testing can be used to show the presence of bugs, but never to show their absence."Edsger Dijkstra
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I read that as "can I have an EXE called whatever and displaying as something else in the taskmanager?".
Ninja (the Nerd)
Confused? You will be...
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hey guys,
I've got a little problem...
I have two classes. One is the member of the other. but the other still needs a pointer to the first.
<br />
#include "B.h"<br />
class A;<br />
class A<br />
{<br />
public:<br />
B m_BClass;<br />
};<br />
<br />
#include "A.h"<br />
class B;<br />
class B<br />
{<br />
public:<br />
A* m_pAClass;
};<br />
somehow this doesn't work...
He gives me:
"Error 4 Error C2143: Syntaxerror: missing ';' before '*'"
cause he doesn't know the class A. Though I forward declarated it.
A friend of mine told me about an "inclusion deadlock". but I cannot figure out how to solve it.
i need to to a global class with all necessary includes.
any hints or links?
thx in advance
PS: should I put the forward deklaration before the "#include" ???
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your problem is you got to forward declare class A is the class B header...this is the only way class B will know about class A, but when using a pointer in class B for class A, you do not have to forward declare, because you are already including the header files for class A inside class B!!!
try taking about the forward declare in both file, I both your files should compile... note in class A you have an auto member to class B object, in this case a forward declare would not be sufficient and you would need to include the header file of class B in the header file of class A.
most of you include should be done in your source file(.cpp) not your header files, unless you like long builds....man there is just too much to talk about this topic and I don't want to get you lost...LOL
Yours Truly, The One and Only!
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yes I tried that, too. but when I want to edit other members of A in B:
<br />
void B::Edit()<br />
{<br />
m_pAClass->somemember = somevalue;<br />
}<br />
I get, of course, somemember is unknown identifier... ???
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Hello,
<br />
#include "B.h"<br />
class A<br />
{<br />
public:<br />
B m_BClass;<br />
<br />
void SayHelloToMyLittleFriend() {}<br />
};<br />
<br />
class A;<br />
class B<br />
{<br />
public:<br />
A* m_pAClass;
<br />
void LetsRock();<br />
};<br />
<br />
#include "B.h"<br />
#include "A.h"<br />
<br />
void B::LetsRock()<br />
{<br />
<br />
m_pAClass->SayHelloToMyLittleFriend();<br />
}<br />
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nice work mate!
Yours Truly, The One and Only!
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